Y = a (x + 3)² - 1
Let's take the point (-1;3)
3 = a ( -1 + 3)² - 1
3 = 4a - 1
4a = 4
Therefore a = 4/4 = 1
(x+3)² - 1
= x² + 6x + 9 - 1
= x² + 6x + 8
The answer would be y = x² + 6x + 8.
Hope this helps !
Photon
For part A: you will get 3 linear factors (as the degree of the polynomial is 3). perform the division using (x-1) as your known factor and you will get (x-1)(2x²+11x+15). you can then factor the (2x²+11x+15) to get 2x^3 + 9x^2 + 4x - 15 = (x-1)(2x+5)(x+3)
for part B: since 2x+5 will provide the greatest value (assuming x>0) of the 3 factors, then 2x+5=13. solve to get x=4. if x is 4, then the dimensions are 3'x13'x7' [just sub 4 into the x's for each factor]
for part C: as to the graphing calculator, I don't have one. However, if you solve each linear factor for when it is 0, those values will be the x-intercepts. So your graph should cross the x-asix at 1, -5/2, and -3
The expression is 2 x3 + 7 =13
Answer:
1/4 +6<t-3
Step-by-step explanation:
the answer is tahta
