I can’t see it , it’s to blurry dude
Answer:
B. negative infinity < x < positive infinity
Step-by-step explanation:
When a question asks for the domain of a function, it is asking for all possible x-values, so we can rule out choice A since there are clearly x-values greater than 1. This graph shows arrows pointing left and downward, indicating that the graph continues past what we can see. This tells us that even though the x-values look like they end at -10 and 2, they continue further, so we can also rule out option C and option D. After these eliminations, we are left with choice B, which is a way of writing "All real numbers," and is the domain for <u>all</u> exponential functions, including this one.
lmk if im incorrect about anything, hope this helps :)
Step-by-step explanation:
![\text{Other solution}\\\\(x^2-y^2)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\= [(x-y)(x+y)]^2\\\\\text{use}\ (ab)^n=a^nb^n\\\\=(x-y)^2(x+y)^2](https://tex.z-dn.net/?f=%5Ctext%7BOther%20solution%7D%5C%5C%5C%5C%28x%5E2-y%5E2%29%5E2%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5C%5C%5C%5C%3D%20%5B%28x-y%29%28x%2By%29%5D%5E2%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%28ab%29%5En%3Da%5Enb%5En%5C%5C%5C%5C%3D%28x-y%29%5E2%28x%2By%29%5E2)
