Note that 9x^2 + 12x +4= 0 has the form of a special product:
(a + b)^2 = a^2 + 2ab + b^2
and so our 9x^2 + 12x +4= 0 factors into (3x + 2)(3x + 2) = (3x + 2)^2
Answer:
− 1 ( 3 2 − 6 + 1 1 )
Step-by-step explanation:
a. 79
Use this theorem