Which quadratic function has a leading coefficient of 2 and a constant term of –3?
2 answers:
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term
<u>We are looking for a = 2, c = -3</u>
Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.
In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2
In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
Answer:
the answer is D
Step-by-step explanation:
just took the test
u r welcome
You might be interested in
In exponential form 720,080 is:
7 × 10^5
+ 2 × 10^4
+ 0 × 10^3
+ 0 × 10^2
+ 8 × 10^1
+ 0 × 10^0
Answer:
The equations that can be graphed are;
y₁=log(2x+1) and y₂=3x-2
Step-by-step explanation:
Answer:
y = -4
Step-by-step explanation:
y = -x-3
Let x= 1
y = -(1) -3
y = -1-3
y = -4
Can't help without a pic or a problem to solve. sorry.
Answer: 3 : 21 3/4
Because it is a enlargement of 3, you need to multiply each side by 3 times.
