Which quadratic function has a leading coefficient of 2 and a constant term of –3?
2 answers:
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f(x) =
- 2
y =
- 2
This is the original equation, and now we have to find the inverse.
When finding the inverse, just flip the variables, x as y and y as x
f ⁻¹(x)
↓
x =
- 2
We have to isolate y as it is our f ⁻¹(x)
Take 2 to the other side { When you see subtraction, you do addition }
x + 2 =
Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y
f ⁻¹ (x) = 9x + 18
f(x) =
y =
This is the original equation, and now we have to find the inverse.
When finding the inverse, just flip the variables, x as y and y as x
f ⁻¹(x)
↓
x =
We have to isolate y as it is our f ⁻¹(x)
Take 2 to the other side { When you see subtraction, you do addition }
x + 2 =
Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y
f ⁻¹ (x) = 9x + 18