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Elis [28]
3 years ago
9

Which quadratic function has a leading coefficient of 2 and a constant term of –3?

Mathematics
2 answers:
Romashka [77]3 years ago
6 0
The answer is <span>f(x) = 2x2 + 3x – 3
</span>
f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term

<u>We are looking for a = 2, c = -3</u>

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: <span>f(x) = –3x2 – 3x + 2
</span>a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3
anastassius [24]3 years ago
5 0

Answer:

the answer is D

Step-by-step explanation:

just took the test

u r welcome

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Answer(s):

If you are asking for the equation, it's 9(x+4)=2

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Step by Step:

1) First we must find the equation. In your question, the unknown number is x. Therefore we can know that "the sum of a number and 4" is (x+4). Since we are multiplying this sum by 9, we can put the 9 in front of this expression to multiply it--getting 9(x+4). And since we know it "is 2" we can say that 9(x+4)=2.

2) Now, we have to solve the equation, 9(x+4) = 2

3) We can start by distributing, 9x+36 = 2

4) Now let's move 36 to the right by subtracting from both sides, 9x = -34

5) To isolate x, let's divide both sides by 9, x = -34/9

6) Our fraction answer can't be simplified, so we get x = -34/9

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3 years ago
I'm supposed to simplify this.
tekilochka [14]

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