5/2x - y < 3
Add y
5/2x < 3 + y
Subtract 3
5/2x - 3 < y
y > 5/2x - 3
Graph "5/2x - 3" and shade the area that is above it
Answer:
second one
Step-by-step explanation:
f(3)=g(3)=6

Let
, so that
:

Now the ODE is separable, and we have

Integrating both sides gives

For the integral on the left, rewrite the integrand as

Then

and so


Given that
, we find

so that the particular solution to this IVP is
