05 22 –27<span> 08 40 37 –03 22 –22 –23 –02 –20 48 53 18 31 –41 –38 –29 –47 30 – 13 46 –07 29 –06 –40 – 19 –20 02 22 20 –06 17 35 31 –01 –37 –34 – 18 –30 ... </span>27 28<span> 10 —ll 16 10 –50 –52 – 10 — 13 35 40 </span>27 28<span> –54 –70 –36 –39 –48 –05 03 03 – </span>12<span> –24 – 13 – 14 – 14 –46 –29 –40 39 </span>60<span> 38 48 –</span>59<span> –</span>59–43<span> –</span>27<span> –</span>44<span> –01 ...ik this didnt help but ill never know if it acually did </span>
2>8-4h/3 subtract 8 from both sides
-6>-4h/3 multiply both sides by 3
-18>-4h divide both sides by -4 (and reverse sign because of division by a negative value)
4.5<h or by convention...
h>4.5
The correct answer is a Trapezoid.
First, I drew and labeled the points on a graph. When these points are connected, you can see that the space between DA and CB is not equal, meaning that the trapezoid is not isosceles.
Each time they assume the sum<span> is </span>rational<span>; however, upon rearranging the terms of their equation, they get a contradiction (that an </span>irrational number<span> is equal to a </span>rational number<span>). Since the assumption that the </span>sum of a rational<span> and </span>irrational number<span> is </span>rational<span>leads to a contradiction, the </span>sum<span> must be </span>irrational<span>.</span>
