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olga55 [171]
3 years ago
15

Roy bought running shoes for $44.98. If the sales tax is 7%, how much did he pay in total?

Mathematics
1 answer:
mario62 [17]3 years ago
8 0

Answer:

$48.13

Step-by-step explanation:

before $44.98

sale tax 7.00% or 3.15

after-tax price $48.13

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Can someone plz help me solved this problem! Need help ASAP! Help me !
lana66690 [7]

Answer:  5, 8

<u>Step-by-step explanation:</u>

The difference between 3 times a number and -8 is BETWEEN 23 and 32

Note: "difference" means subtraction --> 3x - (-8)  --> 3x + 8

               23 < 3x + 8 < 32

               15 < 3x        < 24          <em> subtracted 8 from all 3 sides</em>

-->             5 <   x        <   8          <em>divided 3 from all 3 sides</em>

 

5 0
3 years ago
Don't get this question
solniwko [45]

Answer:

17 and 18

Step-by-step explanation:

Writing every 2 digit number gives us :

10-99 including 10 and 99

For the first one we are looking for numbers where the number 3 appears only once so 33 would be invalid.

13,23,30,31,32,34,35,36,37,38,39,43,53,63,73,83,93

There are 17 2-digit numbers that have 3 exactly once

For the second one we are looking for number where the number 3 appears a minimum of once so 33 would be valid :

13,23,30,31,32,33,34,35,36,37,38,39,43,53,63,73,83,93

There are 18 2-digit numbers that have 3 at least once

Hope this helped and have a good day

5 0
2 years ago
A cars velocity on a straight highway increases uniformly from 20km/h to 70km/h in 0.008h. Find the acceleration in km/h2
Bess [88]

Answer:

a = 70 km/h - 20 km/h / 0.008 h  = 50 km/h / 0.008 h  = 6250 km/h²

3 0
2 years ago
Read 2 more answers
Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
Complete to show how you can find the sum by making a ten, hundred, or thousand.
Andrew [12]

8+5=

8+2+3

10+(-2)

I don't really get it though  

4 0
3 years ago
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