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Nikitich [7]
3 years ago
11

HLPE QUICK PLEASE!! WILL GIVE BRAINLIEST!

Mathematics
2 answers:
alukav5142 [94]3 years ago
6 0

Answer:

C

Explanation not provided

Phoenix [80]3 years ago
4 0

Answer:

A.

Step-by-step explanation:

499.0 seconds which rounds to 500 seconds.

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Multiply<br> ( 4x + 6y ) to the power of two 2<br> what is the answer?
n200080 [17]

Answer:

2

Step-by-step explanation:

4 0
3 years ago
How to do this 24:96 = 5:?
Rama09 [41]
Um... I think you meant <span>24:96 = 5:x

In that case, x=20


</span>
6 0
2 years ago
3. Let U and V be subspaces of a vector space W. Prove that their intersection UnV is also a subspace of W
kenny6666 [7]

Answer:  The proof is done below.

Step-by-step explanation:  Given that U and V are subspaces of a vector space W.

We are to prove that the intersection U ∩ V is also a subspace of W.

(a) Since U and V are subspaces of the vector space W, so we must have

0 ∈ U and 0 ∈ V.

Then, 0 ∈ U ∩ V.

That is, zero vector is in the intersection of U and V.

(b) Now, let x, y ∈ U ∩ V.

This implies that x ∈ U, x ∈ V, y ∈ U and y ∈ V.

Since U and V are subspaces of U and V, so we get

x + y ∈ U  and  x + y ∈ V.

This implies that x + y ∈ U ∩ V.

(c) Also, for a ∈ R (a real number), we have

ax ∈ U and ax ∈ V (since U and V are subspaces of W).

So, ax ∈ U∩ V.

Therefore, 0 ∈ U ∩ V and for x, y ∈ U ∩ V, a ∈ R, we have

x + y and ax ∈ U ∩ V.

Thus, U ∩ V is also a subspace of W.

Hence proved.

7 0
3 years ago
What is 2b + 3c + 5b ? ​
Volgvan

Answer:

7b + 3b

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
P=(-5,5) and Q=(-3,4)
Kay [80]
If you want the slope it's 1/-8
4 0
3 years ago
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