Answer:

Step-by-step explanation:
First, we change both denominators to the LCM (lowest common multiple) which is 8.

Since the denominators are the same, we can add the numerators.


or it can be written as

Answer:
there is no diagram ......
Answer:
The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the population, we have that:
Mean = 15
Standard deviaiton = 12
Sample of 30
By the Central Limit Theorem
Mean 15
Standard deviation 
Approximately normal
The sampling distribution of the sample mean of size 30 will be approximately normal with mean 15 and standard deviation 2.19.
Answer:
0.90
Step-by-step explanation:
I’m doing the unit test
Answer:
step 1. y - y1 = m(x - x1). this is the equation given a point and a slope.
step 2. find the slope m. m = (y2 - y1)/(x2 - x1) = (4 - (-4))/(0 - 2) = 8/-2 = -4.
step 3. y - (-4) = -4(x - 2) ; y + 4 = -4x + 8.
step 4. y = -4x + 4.