Answer:
(a)
1 sig: 0.005
2 sig: 0.0048
3 sig: 0.00482
(b)
1 sig: 50
2 sig: 50.
3 sig: 50.0
(c)
1 sig: 0.0010
2 sig: 0.00098
3 sig: 0.000981
Step-by-step explanation:
Significant Figures Rules:
- Any non-zero digit is significant.
- Any trailing zeros after the decimal is significant.
- Any zeros between 2 significant digits are significant.
- Zeroes before significant numbers in the decimal place are NOT significant; they are placeholders.
(a)
0.004816 - the zeros are placeholders, so they do not count as sig figs.
(b)
50.00168 - the zeros are between 2 significant figures, so they do count as sig figs.
(c)
0.0009812 - the zeros are placeholders, so they do not count as sig figs
Answer:
answer is 57.
Step-by-step explanation:
Given
m<6= x - 8
m<7 = 2x - 7
We know
<6 + <7 = 180° [ being linear pair ]
x - 8 + 2x - 7 = 180°
3x - 15 = 180°
3x = 180° + 15°
3x = 195°
x = 195° / 3
x = 65°
Now
m<6= x - 8 = 65° - 8° = 57°
hope it helps :)
Answer:
z = 113
y = 31
Step-by-step explanation:
j || n and line a is their transversal. (given)
Therefore,
z° = 180° - 67° (exterior angles on the same side of transversal)
z°= 113°
z = 113
(5y - 88)° = 67° (exterior alternate angles)
5y - 88 = 67
5y = 67 + 88
5y = 155
y = 155/5
y = 31
Answer:
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
Step-by-step explanation:
Remember that:
- Two lines are parallel if their slopes are equivalent.
- Two lines are perpendicular if their slopes are negative reciprocals of each other.
- And two lines are neither if neither of the two cases above apply.
So, let's find the slope of each equation.
The first basketball is modeled by:
We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:
And divide both sides by four:
So, the slope of the first basketball is -3/4.
The second basketball is modeled by:
Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:
And divide both sides by negative eight:
So, the slope of the second basketball is also -3/4.
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
