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Alexeev081 [22]
3 years ago
13

so here's my problem from pearson realize lesson 4-8 grade 7 math book. can someone help me int this question

Mathematics
1 answer:
Allushta [10]3 years ago
6 0

a) 0.92v or 23v/25 or 92%v


b)Oringaly, there was 100%. 8% was token away, so 100%-8%=92%


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Identify the GCF of each expression as 2 or 4.
klemol [59]
The GCF for the first one is 4
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The GCF for the third one is 2
The GCF for the fourth one is 4
The GCF for the fifth one is 2
The GCF for the six one is 2
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What ordered pair describes the origin
Georgia [21]

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(0, 0)

Step-by-step explanation:

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A statistician calculates that 7% of Americans are vegetarians. If the statistician is correct, what is the probability that the
son4ous [18]

Answer:

0.0182 = 1.82% probability that the proportion of vegetarians in a sample of 403 Americans would differ from the population proportion by more than 3%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

A statistician calculates that 7% of Americans are vegetarians.

This means that p = 0.07

Sample of 403 Americans

This means that n = 403

Mean and standard deviation:

\mu = p = 0.07

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.07*0.93}{403}} = 0.0127

What is the probability that the proportion of vegetarians in a sample of 403 Americans would differ from the population proportion by more than 3%?

Proportion below 7 - 3 = 4% or above 7 + 3 = 10%. Since the normal distribution is symmetric, these probabilities are equal, which means that we find one of them, and multiply by 2.

Probability the proportion is below 4%

p-value of Z when X = 0.04.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.04 - 0.07}{0.0127}

Z = -2.36

Z = -2.36 has a p-value of 0.0091

2*0.0091 = 0.0182

0.0182 = 1.82% probability that the proportion of vegetarians in a sample of 403 Americans would differ from the population proportion by more than 3%.

6 0
3 years ago
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horsena [70]
Answer: D. 4

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exis [7]

Answer:

B because the input is not the same!

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Not A because the input can't be the same.

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