Ask question

Ask question

All categories

4 years ago

12

Plz help !!!!!!!!!!!

2 answers:

NNADVOKAT [17]4 years ago

4 0

Answer:

the first one

Step-by-step explanation:

the 36 and the 5 stay in the same places

the x with the negative 4 exponent moves to the bottom and combines with x squared so that makes x to the 6th power on the bottom.

The y and x move to the top to combine with what is there.

vodomira [7]4 years ago

3 0

Answer: $\bold{a)\quad \dfrac{36y^5z^2}{5x^6}}$

<u>Step-by-step explanation:</u>

$\dfrac{36x^{-4}y^2z^0}{5x^2y^{-3}z^{-2}}\\\\\\=\dfrac{36x^{-4+4}y^{2+3}z^{0+2}}{5x^{2+4}y^{-3+3}z^{-2+2}}\\\\\\=\dfrac{36x^{0}y^5z^2}{5x^6y^{0}z^{0}}\\\\\\=\dfrac{36y^5z^2}{5x^6}$

You might be interested in

What is the value of x?<br> 99°<br> 35°<br> 81<br> 55<br> 46<br> 134

ruslelena [56]

Answer: 46

Step-by-step explanation:

The angles add to form a straight angle, so x+99+35=180. It follows that x=46.

8 0

2 years ago

Please help solve!!<br> -5|x|+4=14

eduard

Answer:

2

Step-by-step explanation:

|x| means absolute value

|x| means if x is positive or negative, its still positive

-5|x|+4=14

-5|x|=10

|x|= -2

answer is 2

3 0

2 years ago

Read 2 more answers

Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.

Ann [662]

Given:

Consider the given function is:

$f(x)=x^2-8x+13$

To find:

The average rate of change of the function over the interval $-1\leq x\leq 6$ .

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

$m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}$

We have,

$f(x)=x^2-8x+13$

At $x=-1$ ,

$f(-1)=(-1)^2-8(-1)+13$

$f(-1)=1+8+13$

$f(-1)=22$

At $x=6$ ,

$f(6)=(6)^2-8(6)+13$

$f(6)=36-48+13$

$f(6)=1$

Now, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is:

$m=\dfrac{f(6)-f(-1)}{6-(-1)}$

$m=\dfrac{1-22}{7}$

$m=\dfrac{-21}{7}$

$m=-3$

Therefore, the average rate of change of the function f(x) over the interval $-1\leq x\leq 6$ is -3.

6 0

3 years ago

1. Find the distance from point P to QS

12345 [234]

Answer:

5.7 units

Step-by-step explanation:

The distance from point P to QS is the distance from point P (1, 1) to the point of interception R(-3, 5).

Use distance formula to calculate distance between P and R:

$PR = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$P (1, 1) = (x_1, y_1)$

$R(-3, 5) = (x_2, y_2)$

Plug in the values into the formula.

$PR = \sqrt{(-3 - 1)^2 + (5 - 1)^2}$

$PR = \sqrt{(-4)^2 + (4)^2}$

$PR = \sqrt{16 + 16}$

$PR = \sqrt{32}$

$PR = 5.7 units$ (to nearest tenth)

4 0

3 years ago

Which of the binomials below is a factor of this expression? 4x^2 - 25y^2 z^2

Y_Kistochka [10]

Answer:

2x - 5yz is the answer

7 0

3 years ago