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Elis [28]
3 years ago
13

Solve this problem, and identify the percent, amount, and base. What percent of 60 is 45?

Mathematics
2 answers:
alekssr [168]3 years ago
6 0
27% of 60 = 45

hope this helps
- Ashley

vladimir2022 [97]3 years ago
4 0

Answer:

45 is 75% of 60

Step-by-step explanation:

If we want to know what percentage of 60 is 45, our 100% will be 60.

to find out what percentage is 45 we apply a simple rule of three

60 \longrightarrow 100\\  45\longrightarrow x\\ x=\frac{45(100)}{60}= 75

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(2n-9)-(-2.4n+4)Find the difference.
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Answer:

The difference is 4.4n−13.

Step-by-step explanation:

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3 years ago
A pair of hikers, 18 miles apart, begin at the same time to hike toward each other. If one walks at a rate that is 1 mph faster
dsp73

Answer:

The chart below shows Mrs. Thompson's grocery bill. What is the average amount Mrs. Thompson spent on groceries?

A. $58

B. $68

C. $78

D. $340

3 0
3 years ago
A tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay
allsm [11]

Answer:

3. $600,000

Step-by-step explanation:

We have been given that a tenant rented a store to use as a real estate school at a base rent of $1,500 a month. Additionally, the tenant agreed to pay 3% of gross annual sales over $200,000.

Let us find base annual rent.

\text{Base annual rent}=\$1500\times 12\\\\ \text{Base annual rent}=\$18,000

Let us find the amount of rent paid as 3% of gross annual sales.

\$30,000-\$18,000=\$12,000

Let us find amount of sales over $200,000 by dividing $12000 by 3% or 0.03.

\frac{\$12,000}{0.03}=\$400,000

Total sales would be $400,000 plus $200,000.

\text{Total sales}=\$400,000+\$200,000\\\\ \text{Total sales}=\$600,000

Therefore, the total sales for that year was $600,000 and 3rd option is the correct choice.

7 0
3 years ago
Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz
klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

A.

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

B.

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

C.

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0
3 years ago
Read 2 more answers
15, 16, 20, and 22! PLEASE HELP
Vikentia [17]
The answer for number 16 is 20
7 0
3 years ago
Read 2 more answers
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