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3 years ago

FAST!!!

Mathematics

1 answer:

Sever21 [200]3 years ago

6 0

Answer:

graph A is the answer because the M is at the 3 and it move up 5

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1.Ordenar de menor a mayor los siguientes números

Nataliya [291]

1. -16, -9, -3, 0, 5, 8, 25

2. 26, 13, 7, 6, 2, -1, -3, -50

Espero que esto ayude!

8 0

3 years ago

Read 2 more answers

The lengths of the sides of a triangle are x, 2x + 1, 5x + 4 inches. If the perimeter is 53 inches, what is thevalue of x?

satela [25.4K]

Answer: 6

Explanation:

x + 2x + 1 + 5x + 4 = 53
8x + 5 = 53
8x = 48
x = 6

5 0

3 years ago

I need to get the left side to equal the right side. Keeping the right side alone and not changing it.

likoan [24]

<u>To prove the trigonometric equation:</u>

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

$RHS=(\sin x+\cos x)(1-\sin x \cos x)$

We know that $\sin^2x +\cos^2x=1$ , substitute this in place of 1.

$=(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)$

Multiply each term of the first term with each term of the 2nd term.

$=\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x$

Group like terms together.

$=\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x$

$=\sin^3x +( 0)+(0) + \cos^3 x$

$=\sin^3x + \cos^3 x$

= LHS

RHS = LHS

$\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)$

Hence proved.

7 0

3 years ago

Simplify -3x^3(2x^2+3)+9x^4

SIZIF [17.4K]

Answer:

ANSWER = −6x^5 +9x^4 − 9x^3

Step-by-step explanation:

Let's simplify step-by-step.

(−3x^3) (2x^2 + 3) + 9x^4

Distribute:

=(−3x^3) (2x^2) + (−3x^3) (3) + 9x^4

=−6x^5 + − 9x^3 + 9x^4

Answer:

= −6x^5 +9x^4 − 9x^3

3 0

3 years ago

Suppose John opens a savings account with $1,000 that compounds interest daily. The APR at the time John deposits the account is

Fed [463]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
\left. \qquad \qquad \right.\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 3.5\%\to \frac{3.5}{100}\to &0.035\\
n=
\begin{array}{llll}
\textit{times it compounds per year}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.035}{365}\right)^{365}-1$

4 0

3 years ago