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3 years ago

How to do word math problems

Mathematics

2 answers:

Lana71 [14]3 years ago

8 0

First u need to read the problem second annalyze 3 create ecuation 4 solve 5 write it in words

Savatey [412]3 years ago

6 0

First, you should read through the word problem twice. The 2nd time you read it, you should circle important information provided to you. Then, you should really think about what the problem is trying to tell you. Next, you can use the information given to create an equation or some sort of representation of what the word problem means. Sometimes, it is also useful to consider the information that is left out.

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Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago

If the width of a rectangle is(x + 5) cm and its perimeter is (10x + 26) cm.

zaharov [31]

Answer:

10x + 26 = 2x + 58

10x = 58-26

10x = 32

X = 3.2

I think??

3 0

3 years ago

Does a line always sometimes or never have end points

luda_lava [24]

A line never has end points. It goes forever in both directions. A segment always has points. A ray has one point and goes forever in one direction. The answer is always. Hope this helps! ;)

6 0

4 years ago

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What is the image point of ( 4 , − 6 ) (4,−6) after a translation right 5 units and up 4 units?

Stella [2.4K]

Answer:

(9,-2)

Step-by-step explanation:

5 is the x coordinate, and 4 is the y coordinate. When you go right a certain amount of units, you add those units to your x coordinate. If you were to go left a certain amount of units, you'd subtract them. Since we're going right, 5 + 4 = 9. When you go up a certain amount of units, you add those units to you y coordinate. If you were to go down a certain amount of units, you'd subtract them. Since we're going up, -6 + 4 = -2. So, x = 9 and y = -2, or (9,-2)

3 0

3 years ago

Hbdudibeww hr h erwknjnnjnjknjnjbhbbh

vagabundo [1.1K]

Answer:

I left my scooter outside the dairy nek minnit.

6 0

3 years ago