Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
I am pretty sure that B is the answer
Answer:
x= 81°, z= 99°, y°=68°
Step-by-step explanation:
considering the part of the triangle where 36° , 63° and x° is located as ΔABC.
to find the measure of x we use angle sum property.
We know that the sum of the angles of a triangle is always 180°. Therefore, if we know the two angles of a triangle, and we need to find its third angle, we use the angle sum property. We add the two known angles and subtract their sum from 180° to get the measure of the third angle.
so,
∠A + ∠B +∠C = 180°
36° + 63° + x° = 180°
99° + x° = 180°
x° = 180 - 99
x° = 81°
When two lines intersect each other at a single point, linear pairs of angles are formed. If the angles so formed are adjacent to each other after the intersection of the two lines, the angles are said to be linear. If two angles form a linear pair, the angles are supplementary, whose measures add up to 180°.
x° + z° = 180°
81° + z = 180°
z= 180 - 81
z= 99°
considering the next part of the triangle where 13° , z° and y° is located as ΔACD
to find the measure of y we use angle sum property.
∠A + ∠C + ∠D = 180°
13° + z° + y° = 180°
13°+99°+y°= 180°
112°+ y° = 180°
y°= 180- 112
y° = 68°
