True is the answer................
The Benedict’s Test is the test which can detect carbohydrates and glucose in foods. During this process, the sample or the food is placed into a test tube and then some drops of Benedict's solution is added to it,and is then put into a beaker of boiling water. When the mixture of food and the Benedict substance turns reddish orange instead of staying blue, this means that it is positive. The mixture has simple sugar or has carbohydrates or glucose. On the other hand, lipids are tested using the brown paper test. When the paper turns transparent when a drop of food is put into it, it means that is is positive as well. When you want to test if the food has proteins, you have to test it with Biurets. Observe if the color change when you put some Biurets solution to the food sample. It is positive if the food turns light purple. Test if the food is positive with starches through the use of iodine. Food having iodine drops should turn purple instead of staying a yellow color.
Answer:
See
Explanation:
Given:
Brown allele (B) is dominant over the white allele (b).
It will be assumed that the alleles are not related to the X and Y chromosomes.
See attached diagram for details of the general case (for both homo-zygous and hetero-zygous parents)
For both parents hetero-zygous,
P1:
Genotype: Bb (100%)
Phenotype: brown (100%)
F1:
Genotypes : BB, Bb, bB and bb in equal proportions, i.e.
BB (25%), Bb (50%), bb (25%)
Phenotypes: 75% brown (from BB and Bb), 25% white (from bb)
Answer:
This is due to the event of Speciation that happened for the rodents in Island B but not for the rodents in Island C.
Explanation:
- Due to splitting of the population,
- The sub-population of rodents formed in Island B are B1 and B2.
- The sub-population of rodents formed in Island C are C1 and C2.
- In case of Island B, each of the B1 and B2 sub-populations that got split from each other developed certain mutations that were necessary for them to adapt to the particular diverse environment each of them were exposed to, through the period of 50,000 years. These mutations were so varied that reproductive isolation was generated between them that resulted in each of them to develop into different species.Hence, speciation happens here and B1 and B2 are incapable of inter-breeding.
- In case of Island C, each of the C1 and C2 sub-populations that got split might have got exposed to similar environmental change or no environmental change or the environmental change might have been too small to cause drastic change in each of the sub-populations. As a result of this the two sub-populations might have acquired certain mutations to adapt to the environment each of them were exposed to, through a period of 100,000 years. These mutations might not have been too variable or contrasting to cause reproductive isolation between C1 and C2. Hence, no new speciation happens here and C1 and C2 are capable of inter-breeding.
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