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blondinia [14]
3 years ago
6

ASAP BRAINLIEST AND POINTS Figure ABCD is reflected across the x-axis. What are the coordinates of A' , B' , C' , and D' ? Enter

your answer in each box. A' (​ ​, ​ ​) B' (​ ​, ​ ​) C' (​ ​, ​ ​) D' ( ​​, ​​) Coordinate plane. The horizontal axis ranges from negative 10 to 10 in increments of 1. The vertical axis ranges from negative 10 to 10 in increments of 1. Quadrilateral A B C D has vertices A at negative 1 comma 4, B at negative 5 comma 8, C at negative 5 comma 4, and D at negative four comma 2.
Mathematics
1 answer:
fgiga [73]3 years ago
6 0

Answer:

The reflecting across the x-axis, then all x component is unchanged, let's change the sign of y component only.

We have

A(-1,4) => A'(-1,-4)

B(-5,8) => B'(-5,-8)

C(-5,4) =>C'(-5,-4)

D(-4,2) => D'(-4,-2)

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Answer:

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

The lower limit on the confidence interval is -$2164.21.

The upper limit on the confidence interval is -$299.13.

Step-by-step explanation:

The sample data is:

Gender   Mean          Std. dev.     n

Female    2577.75      1916.29     67

Male        3809.42     2379.47     33

We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The sample 1, of size n1=67 has a mean of 2577.75 and a standard deviation of 1916.29.

The sample 2, of size n2=33 has a mean of 3809.42 and a standard deviation of 2379.47.

The difference between sample means is Md=-1231.67.

M_d=M_1-M_2=2577.75-3809.42=-1231.67

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1916.29^2}{67}+\dfrac{2379.47^2}{33}}\\\\\\s_{M_d}=\sqrt{54808.468+171572.045}=\sqrt{226380.513}=475.795

The t-value for a 95% confidence interval is t=1.96.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.96 \cdot 475.795=932.54

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -1231.67-932.54=-2164.21\\\\UL=M_d+t \cdot s_{M_d} = -1231.67+932.54=-299.13

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

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