Given that the line is x/3 + y/2 =1 i ) make y the subject ii ) gradient of line
1 answer:
Answer:
see explanation
Step-by-step explanation:
(i)
+
= 1 ( multiply through by 6 to clear the fractions )
2x + 3y = 6 ( subtract 2x from both sides )
3y = - 2x + 6 ( divide through by 3 )
y = - x + 2
(ii)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope ( gradient ) and c the y- intercept )
y = - x + 2 ← is in slope- intercept form ( that is part (i)
with gradient m = -
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<h3>Axis of symmetry is 0 and vertex is (0, -1)</h3>
<em><u>Solution:</u></em>
<em><u>Given is:</u></em>
We have to find the vertex and axis of symmetry
<em><u>The general equation is given as:</u></em>
Comparing with given equation,
a = 2
b = 0
c = -1
<em><u>The axis of symmetry is given as:</u></em>
Thus axis of symmetry is 0
The x coordinate of the vertex is the same
x coordinate of the vertex = 0
h = 0
The y coordinate of the vertex is:
k = f(h)
k = f(0)
Thus, y coordinate of the vertex is -1
Therefore, vertex is (0, -1)