Given that the line is x/3 + y/2 =1 i ) make y the subject ii ) gradient of line
1 answer:
Answer:
see explanation
Step-by-step explanation:
(i)
+
= 1 ( multiply through by 6 to clear the fractions )
2x + 3y = 6 ( subtract 2x from both sides )
3y = - 2x + 6 ( divide through by 3 )
y = - x + 2
(ii)
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope ( gradient ) and c the y- intercept )
y = - x + 2 ← is in slope- intercept form ( that is part (i)
with gradient m = -
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A graph of the equation shows the appropriate choice to be
C. 2
_____
If you would rather, you can look at the value of the discriminant. For the equation y = ax²+bx+c, the discriminant (d) is
d = b²-4ac
For your equation, this evaluates to
d = (-8)²-4(2)(5) = 64 -40 = 24
When the discriminant is positive, the function has two real roots (2 x-intercepts). When it is zero, there is only one x-intercept, and when it is negative, there are none (the roots are complex).
C. 2
_____
If you would rather, you can look at the value of the discriminant. For the equation y = ax²+bx+c, the discriminant (d) is
d = b²-4ac
For your equation, this evaluates to
d = (-8)²-4(2)(5) = 64 -40 = 24
When the discriminant is positive, the function has two real roots (2 x-intercepts). When it is zero, there is only one x-intercept, and when it is negative, there are none (the roots are complex).