Answer:
if you go on google mathematics and type it in youll get it right away
Step-by-step explanation:
Answer: Brielle will run the marathon faster.
Brielle = 104.8 minutes
Joshua = 157.2 minutes
Step-by-step explanation:
Speed rate = distance /time
Brielle = 1.25 /10 = 0.125 miles per minute
Joshua = 1.5/18 = 0.083333 =1/12 miles per minute
Since 0.125 (Brielle) > 1/12 (Joshua)
Brielle will run the marathon faster.
To calculate the time that takes each one to run the entire race (13.1 miles)
Time= distance / speed
- Brielle = 13.1 /0.125 = 104.8 minutes
- Joshua = 13.1 / (1/12)= 157.2 minutes
Feel free to ask for more if needed or if you did not understand something.
Sorry. It's not clear. Plz tell me if there is 12 3/8in?
Answer:



The standard deviation will remain unchanged.
Step-by-step explanation:
Given

Solving (a): The range
This is calculated as:

Where:

So:


Solving (b): The variance
First, we calculate the mean




The variance is calculated as:

So, we have:
![\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B6-1%7D%2A%5B%28136%20-%20135%29%5E2%20%2B%28129%20-%20135%29%5E2%20%2B%28141%20-%20135%29%5E2%20%2B%28139%20-%20135%29%5E2%20%2B%28138%20-%20135%29%5E2%20%2B%28127%20-%20135%29%5E2%5D)
![\sigma^2 =\frac{1}{5}*[162]](https://tex.z-dn.net/?f=%5Csigma%5E2%20%3D%5Cfrac%7B1%7D%7B5%7D%2A%5B162%5D)

Solving (c): The standard deviation
This is calculated as:


--- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.
Answer:
f(2) = 3
Step-by-step explanation:
We are given:
f(0) = 3
and
f(n+1) = -f(n) + 5
We have to find the value of f(2). In order to find f(2) we first have to find f(1)
f(n + 1) = - f(n) + 5
Using n = 0, we get:
f(0 + 1) = - f(0) + 5
f(1) = -f(0) + 5 Using the value of f(0), we get
f(1) = -3 + 5 = 2
Now using n = 1 in the function, we get:
f(1 + 1) = - f(1) + 5 Using the value of f(1), we get
f(2) = -2+ 5
f(2) = 3
Thus the value of f(2) will be 3