All categories

3 years ago

Is negative two less than negative one?

Mathematics

2 answers:

Juliette [100K]3 years ago

5 0

Answer:

Yes negative two is less that negative one. The farther you move to te left of zero the smaller the number becomes.

geniusboy [140]3 years ago

3 0

Answer:

Yes.

Step-by-step explanation: The confusing thing about negetives is the greater the negetive number is, the less the value is. think of a number line. the farther the number is to the left, the smaller it is.

You might be interested in

Clara ate 1/8 of the pie Jacob ate 1/4 how much of the pie did they ate

nika2105 [10]

They ate 3/8 of the pie because 1/4=2/8 .and 1/8+2/8=3/8. Hope this helps

5 0

3 years ago

Read 2 more answers

an isosceles triangle has angle measures of 55, 55, and 70. the side across the 70 degree angle is 10 inches long. how long are

Shtirlitz [24]

Answer:

The other sides of triangles are 8.72 in and 8.72 in

Step-by-step explanation:

In a triangle ABC. Please find the attachment for figure.

$\angle A=70^{\circ}$

$\angle B=\angle C=55^{\circ}$

Side BC=a = 10 in

Using sine law of trigonometry,

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

Substitute the given value into formula.

$\dfrac{10}{\sin 70}=\dfrac{b}{\sin 55}=\dfrac{c}{\sin 55}$

$\dfrac{10}{\sin 70}=\dfrac{b}{\sin 55}$

Cross multiply and we get

$b=\sin 55\times \dfrac{10}{\sin 70}$

$b=8.72$ in

It is a isosceles triangle. Therefore, b=c=8.72 in

Hence, The other sides of triangles are 8.72 in and 8.72 in

7 0

3 years ago

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago

Afan pays $875 for 3 premium seat tickets. Another fan pays $2125 for 8 premium seat tickets. Write a linear model for the cost

grandymaker [24]

The equation is : C=250t +125 where C is the cost and t represent the number of tickets purchased.

Step-by-step explanation:

Let the cost of premium seat ticket be C

Let the number of tickets a fan buys to be t

Then, presenting the information as ordered pairs of coordinates (x,y) will be;

Fan 1, (3,875)

Fan 2, (8,2125)

Plot the ordered pairs as coordinates on a graph tool, find the slope of the linear graph and equation in slope intercept form as;

m=Δy/Δx

m=2125-875/8-3

m=1250/5

m=250

Equation of the graph,

Δy/Δx=250

y-875/x-3 =250

y-875=250(x-3)

y-875=250x-750

y=250x-750+875

y=250x+125

C=250t +125 where C is the cost and t represent the number of tickets purchased

Learn More

Slope-intercept form equation: brainly.com/question/11016508

Keyword : slope-intercept form,cost

#LearnwithBrainly

7 0

3 years ago

Which value is a solution of the equation 2 - 8x = -6?<br> A. 1<br> B. 1/2<br> C. -1<br> D. 8

Nuetrik [128]

Answer:

A.) 1

Step-by-step explanation:

First change the equation to 2 + ( - 8x ) = -6 so it’s easier to read

Take away 2 from both sides

So now you have -8x = -8

Divide both sides by -8 so you get positive x and 1

x = 1

3 0

3 years ago