Which variable would you like to solve for?
Let's try solving for y since you have two of them.
ky - bf = fy/m
kym - bfm = fy --> [ multiply by m ]
kym - fy = bfm --> [ subtract fy on both sides ]
y(km-f) = bfm ---> [ factor out a y ]
y = bfm/(km-f) ---> [ divide by km-f on both sides ]
<span>36 does not belong in that group because it is the only number that is not a power of 2:
2^2 OR 2 x 2 = 4
2^3 OR 2 x 2 x 2 = 8
2^4 OR 2 x 2 x 2 x 2 = 16
2^5 OR 2 x 2 x 2 x 2 x 2= 32
2^6 OR 2 x 2 x 2 x 2 x 2 x 2= 64</span>
Answer:
is their any way I can get some more info on this problem
Step-by-step explanation:
Using the distributive property, we have -12w^2-2w since a(b+c)=ab+ac
Hope this helped
