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Brilliant_brown [7]
2 years ago
15

What is the solution to the equation 2/3a-1/6=1/3

Mathematics
1 answer:
Vsevolod [243]2 years ago
4 0

Answer:

a = \frac{3}{4}

Step-by-step explanation:

\frac{2a}{3} -\frac{1}{6} =\frac{1}{3}

\frac{4a}{6}-\frac{1}{6}  =\frac{2}{6}

(now you can multiply the whole equation by 6 to remove the fractions

4a - 1 = 2

4a = 2+1

4a = 3

a = \frac{3}{4}

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In the adjoining figure, the parallel lines are marked by arrow lines. The value of angle 1 is:
dlinn [17]

Answer:

20°

Step-by-step explanation:

40°, 70° and 90° are the measures of the three angles of the quadrilateral.

Measure of fourth angle of the Quadrilateral

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Thus,

m\angle 1 = 180\degree- 160\degree

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Alternate method:

m\angle 1 = 180\degree- [360\degree-(40\degree+70\degree+90\degree)]

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The vertices of a polygon are P(0,4), Q(5,4), R(5,−3) and S(0,−3). What is
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Answer:

 Perimeter of the polygon p = 24

Step-by-step explanation:

Step(i):-

Given the vertices of a polygon are

P(0,4) ,Q( 5,4) ,R( 5,-3) and S(0,-3)

The distance of PQ

 a = PQ = \sqrt{(4-4)^{2} +(5-0)^{2} }  = \sqrt{25} =5

The distance of QR

b = Q R= \sqrt{(-3-4)^{2} +(5-5)^{2} }  = \sqrt{49} =7

The distance of RS

c = RS = \sqrt{(0-5)^{2} +(-3+3)^{2} }  = \sqrt{25} =5

The distance of PS

d = PS = \sqrt{(0-0)^{2} +(-3-4)^{2} }  = \sqrt{49} =7

<u><em>Step(ii):-</em></u>

Perimeter of the polygon

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p = 24

<u><em>Final answer:-</em></u>

 Perimeter of the polygon p = 24

5 0
3 years ago
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