Use the graph below to answer the question that follows:
2 answers:
Answer:
D) Amplitude: 2; period: π; midline: y = 1
Step-by-step explanation:
The question is much more easily answered from the graph than from the description of the graph.
The amplitude is the extent of the peak above the midline (2), or half the peak-to-peak value (4/2=2). The midline is the line halfway between the peaks (1). The period is the horizontal distance between peaks of the same polarity (π).
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Answer:
16) 62.8 m²
17) 19.4 m²
18) 103.5 m²
Step-by-step explanation:
The formula to find area of a circle is: . To find radius, find the half of the diameter.
To solve number 16, first find the area of the unshaded circle using the formula: . This is also 3.14*16. Multiply to get 50.24 m². Now find the area of the larger circle using the formula:
. This is also 3.14*36. Multiply to get 113.04 m². Now subtract 113.04 - 50.24 to get the shaded area or 62.8 m².
To solve number 17, first find the area of the square using the formula: side x side. In this case multiply: 5.25 x 5.25 to get 27.5625. Round to the nearest tenth to get 27.6 m². Now find the area of the circle using the formula: . This is also 3.14*2.625. Multiply to get 8.2425. Round to the nearest tenth to get 8.2. Subtract 27.6 - 8.2 to get 19.4 m².
To solve number 18, find the area of one unshaded circle using the formula: . This is also 3.14*3.0625. Multiply to get 9.61625. Round to the nearest tenth to get 9.6 m². Add 9.6 + 9.6 to find the area of both unshaded circles. You get 19.2 m². Now find the area of the shaded circle using the formula:
. This is also 3.14*39.0625. Multiply to get 122.65625. Round to the nearest tenth: 122.7. Subtract 122.7 - 19.2 to get 103.5 m².
Hope it helps and is correct!