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bixtya [17]
3 years ago
5

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam. They had 504 chocolates altogether. How m

any more chocolates did Clarissa have at first?
Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

315 chocolate

Step-by-step explanation:

Let Sam's chocolate be S

Let Clariss's chocolate be C

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.

This can be written as:

C = 5S

The sum of their chocolate is 504 i.e

S + C = 504

Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:

S + C = 504

But: C = 5S

S + 5S = 504

6S = 504

Divide both side by 6

S = 504/6

S = 84.

C = 5S = 5 x 84 = 420

Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.

Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:

Amount of chocolate that Clarissa has a first = 420 – 105 = 315

Therefore, Clarissa had 315 chocolate at first.

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Step-by-step explanation:

Given:

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sp2606 [1]

The perimeter of the pentagon with apothem of 5cm is 28.87cm

<h3>How to calculate the perimeter of a pentagon</h3>

The sum of all the external sides of the pentagon is its perimeter.

First we need to calculate the half of one of its sides using the SOH CAH TOA

tan 30 = x/5

x = 5 tan 30

x = 2.89

One of the sides = 2(2.89) = 5.77 cm

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