from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.
likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D8.5%5C%5C%20a%3D24.3%5C%5C%20b%3D9.7%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B8.5%2824.3%2B9.7%29%7D%7B2%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B8.5%2834%29%7D%7B2%7D%5Cimplies%20A%3D144.5~in%5E2%20%5Cend%7Barray%7D)
Answer:
I honestly don’t know I am gonna guess
Step-by-step explanation:
1/12?
. 。 • ゚ 。 . .
. . 。 。 . .
. 。 ඞ 。 . • • .
.
゚ Bread was Not An Impostor. 。 . .
' 1 Impostor remains 。 .
゚ . . , . .. . .
Have a nice day UwU
Answer:
2 : 3
Step-by-step explanation:
<em>Hello fellow human!</em>
red : blue - 8 : 12
The ratio is divisible by 4 - (8/4) = 2 ; (12/4) = 3
Hence, 2 : 3
Answer:
(2l + 2w) + (a + b + c)
Step-by-step explanation:
The formula for the perimeter of a rectangle is
P = 2l + 2w
so if you substitute, it becomes
P = 2(12) + 2(2)
= 24 + 4
= 28
For the perimeter of a triangle the correct formula would be
P = a + b + c
The missing side in the triangle is 3 because 15 - 12 is 3.
If you substitute, it becomes
P = 2 + 3 + 6
P = 11
If we add both perimeters together we get the full perimeter of the figure which is
28 + 11 = 39
I am not sure if you wanted the answer as well but just in case :)