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Murljashka [212]
3 years ago
14

The ratio of boys to girls in band class was 3 to 5. If there were 24 boys. How many girls were in band class?

Mathematics
2 answers:
Tamiku [17]3 years ago
7 0

Answer:

40 girls

Step-by-step explanation:

Set up a proportion where x is the number of girls in band class:

\frac{3}{5} = \frac{24}{x}

Cross multiply and solve for x:

3x = 120

x = 40

So, there were 40 girls in band class.

Mama L [17]3 years ago
6 0

Answer: There are 40 girls in band class.

____________________________________________________________

The ratio for this problem is:

\frac{3}{5} = \frac{24}{x}

To get from 3 to 24, you would multiply by 8. You need to do the same thing to 5 to get x.

5 times 8 equals 40.

There are 40 girls in band class.

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Solve, then write, each equation in slope intercept form. ​
djyliett [7]

Answer:

1) (3,5)

2) (4,-7)

3)  (6,4)

4) (-4,-3)

Step-by-step explanation:

1)

Subtract  y  from both sides of the equation.

x  =  8  −  y

x  −  y  =  −2

Replace all occurrences of x  in x  −  y  =  −2  with  8  −  y.

x  =  8  −  y

(8  −  y)  −  y  =  −2

Subtract y from  −y.

x  =  8  − y

8  −  2y  =  −2

Solve for  y  in the second equation.

x  =  8  −  y  

y  = 5

Replace all occurrences of  y  in  x  =  8  −  y  with  5.

x  =  8  −(5)

y  =  5

Simplify  8  −(5).

x  =  3

y  =  5

Slope = (3,5)

2)

Multiply each term by  2  and simplify.

2x+y=12

y+6=−x−4

Move all terms containing variables to the left side of the equation.

2x+y=1x+2

y+6=−4

Move all terms not containing a variable to the right side of the equation.

2x+y=1x+2

y=−10

Multiply each equation by the value that makes the coefficients of  x  opposite.

2x+y=1(−2)⋅

(x+2y)=(−2)(−10)

Simplify.

2x+y=1−2x−4

y=20

Add the two equations together to eliminate  x  from the system.

2x+y=1+−2x−4

y=20−3

y=21

Divide each term by  −3  and simplify.

y  = −7

Substitute the value found for  y  into one of the original equations, then solve for  x.

x  =  4

slope (4,-7)

3)

Subtract  y  from both sides of the equation.

2x−y=8x−y=2

Multiply each equation by the value that makes the coefficients of  y  opposite

2x−y=8(−1)⋅

(x−y)=(−1)(2)

Simplify. 2x−y=8

−x+y=−2

Add the two equations together to eliminate  y  from the system.

2x−y=8  +  −x+y=−2x=6

Substitute the value found for  x  into one of the original equations, then solve for  y.

y=4

slope (6,4)

4)

Simplify 2(x+1).

y−3=2x+2

y=−3(x+5)

Simplify  −3(x+5)

y−3=2x+2

y=−3x−15

Move all terms containing variables to the left side of the equation.

−2x+y−3=2

y=−3x−15

Add  3x  to both sides of the equation.

−2x+y−3=2

y+3x=−15

Move all terms not containing a variable to the right side of the equation.

−2x+y=5

y+3x=−15

Reorder the polynomial.

−2x+y=5

3x  +  y=−15

Multiply each equation by the value that makes the coefficients of  y  opposite.

−2x+y=5(−1)⋅

(3x+y)=(−1)(−15)

Simplify.

−2x+y=5

−3x−y=15

Add the two equations together to eliminate  y  from the system.

−2x+y=5  +  −3x−y=15−5x=20

Divide each term by  −5  and simplify.

x=−4

Substitute the value found for  x  into one of the original equations, then solve for y.

y=−3

slope (-4,-3)

4 0
3 years ago
Write an expression for 20 times the sum of 4 and 2
marta [7]

Answer:

20x6

Step-by-step explanation:

20x (x stands for multiply/times)

6(sum/add 4+2)

20x6

Hope this helps.

8 0
3 years ago
Read 2 more answers
A quadrilateral has two angles that measure 222° and 81°. The other two angles are in a ratio of 6:13. What are the measures of
hram777 [196]

\sf\huge\underline{\star Solution:-}

\rightarrow <u>Ratio of two angles are 6:13.</u>

So, let the one angle be \sf{6x} and another be \sf{13x.}

As we know that,

Sum of all interior angles of a quadrilateral = \sf\pink{360°.}

So let's sum up the given angles,

\rightarrow \sf{222°+81°+6x+13x \:=\:  360°}

\rightarrow \sf{303+19x \:=\:  360°}

\rightarrow \sf{19x \:=\:  360-303}

\rightarrow \sf{19x \:=\:  57}

\rightarrow \sf{x \:=\:  \frac{19}{57}}

\rightarrow \sf{x \:=\:  3}

Hence, \sf{x \:=\:  3}

So, First angle \sf{= \:6x\: = \:6×3 \:=} \sf\purple{18°.}

Second angle \sf{= \:13x\: = \:13×3 \:=} \sf\purple{39°.}

_________________________________

Hope it helps you:)

3 0
2 years ago
Graph the line with the equation y = 1/6x-5<br><br> PLEASE HELP
quester [9]

Answer:

Step-by-step explanation:

5 0
2 years ago
One angle measure in an acute triangle is 38°. What could the measure of one of the other angles be?
aivan3 [116]
Acute, Obtuse, Acute, Acute
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3 years ago
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