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yarga [219]
3 years ago
15

Solve for the missing x coordinate above

Mathematics
1 answer:
Cloud [144]3 years ago
7 0
The unknown vertex is on the perpendicular bisector of the opposite side.  So the x coordinate is the same as that of the midpoint, x=(18+52)/2=35.


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Hellllppppppppppppppp meeeeeeeeeeeee
Alexxandr [17]

Answer:

D. 20

Step-by-step explanation:

20% of 20 is 4

6 0
2 years ago
Read 2 more answers
Tell wether x and y show a proportional relationship.<br><br> x 1 2 3 4<br> y 4 8 12 16
Delicious77 [7]

Answer:

They do because y is always 4 times of x.

Step-by-step explanation:

7 0
3 years ago
the function h(t)=-16t2+144 represents the height, h(t), in feet, of an object from the ground at t second after its dropped. A
blagie [28]
The domain is the limits of the function. Since time doesnt go negative, start with 0. At time 0, the height is

-16(0)^2 + 144 = 144ft

Then, solve for t to find the upper limit for t, which is when the height is zero (since you're dropping the object).

-16t^2 + 144 = 0
-16t^2 = -144
t^2 = 9
t = sqrt(9)
t = 3

The domain is 0 to 3 seconds.
5 0
3 years ago
Simplify (9x^3-4x+10)+(x^3+10x-9)
Alex

Simplify

9x^3 - 4x + 10 + x^3 + 10x - 9

Collect like terms

(9x^3 + x^3) + (-4x + 10x) + (10 - 9)

Simplify

<u>10x^2 + 6x + 1</u>

6 0
3 years ago
Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5
zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}} or \displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as \displaystyle \large{a_{n-1} \cdot r = a_n} meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as:

\displaystyle \large{r=\frac{a_{n+1}}{a_n}}

Once knowing which sequence or series is it, apply an appropriate formula for the series. For geometric series, apply the following three formulas:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}\\\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

Above should be applied for series that have common ratio not equal to 1.

\displaystyle \large{S_n=a_1 \cdot n}

Above should be applied for series that have common ratio exactly equal to 1.

__________________________________________________________

Topics

Sequence & Series — Geometric Series

__________________________________________________________

Others

Let me know if you have any doubts about my answer, explanation or this question through comment!

__________________________________________________________

7 0
2 years ago
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