All categories

3 years ago

What is each sum or difference?

Mathematics

1 answer:

elena-s [515]3 years ago

5 0

1. 4-i
2. -2+3i
3. 0
4. 18i

You might be interested in

Find the area of an octagon with a radius of 6 meters. Round your answer to the nearest tenth.

Ludmilka [50]

Hope it can help u, but i dont known it right or wrong, if any wrong, it is very sorry for you...

6 0

3 years ago

What is the average rate of change of f(x), represented by the table of values, over the interval [-3, 4]? x f(x) -6 27 -3 6 -1

USPshnik [31]

Answer:

The correct option will be: C. 3

Step-by-step explanation:

The given table is..........

$x :$ -6 -3 -1 0 1 4

$f(x) :$ 27 6 2 3 6 27

The formula for average rate of change is: $\frac{f(b)-f(a)}{b-a}$ , where $[a,b]$ is the given interval.

Here the interval is [-3, 4]. So, $a=-3$ and $b=4$

Now, plugging the values of $a$ and $b$ into the above formula, we will get........

$\frac{f(4)-f(-3)}{4-(-3)}$

From the given table, we will get $f(4)=27$ and $f(-3)=6$

So, the average rate of change will be: $\frac{27-6}{4-(-3)}= \frac{21}{7}=3$

3 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. 7x2 + xy + 7y2 = 15, (1, 1

riadik2000 [5.3K]

Assume $y=y(x)$ .

$7x^2+xy+7y^2=15$
$\dfrac{\mathrm d}{\mathrm dx}[7x^2+xy+7y^2]=\dfrac{\mathrm d}{\mathrm dx}[15]$
$14x+y+x\dfrac{\mathrm dy}{\mathrm dx}+14y\dfrac{\mathrm dy}{\mathrm dx}=0$
$\dfrac{\mathrm dy}{\mathrm dx}(x+14y)=-(14x+y)$
$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{14x+y}{x+14y}$

The slope of the tangent line to the curve at $(a,b)$ is then $-\dfrac{14a+b}{a+14b}$ , so the tangent to $(1,1)$ has slope

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=-\dfrac{15}{15}=-1$

The point-slope form of the tangent line is then

$y-1=-(x-1)\iff y=-x+2$

7 0

3 years ago

Need help before 7:00am tomorrow morning

yan [13]

The answer to question 4 is C, (16,20)

8 0

3 years ago

Read 2 more answers

Question 10

Bond [772]

Answer:

( x - 2)^2 + ( y - 3)^2 = 34

Step-by-step explanation:

The equation of the circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( a, b) - the center of the circle

( x, y) - any point on the circle

r^2 - radius of the circle

( -3 , 6) - point - ( x, y)

x = -3

y = 6

( 2 , 3) - center-( a, b)

a = 2

b = 3

Step 1: substitute the center into the equation

( x - 2)^2 + ( y - 3)^2 = r^2

Step 2: sub the point into the equation

( x - 2)^2 + ( y - 3)^2 = r^2

( -3 - 2)^2 + ( 6 - 3)^2 = r^2

( -5)^2 + 3^2 = r^2

25 + 9 = r^2

34 = r^2

Step 3: sub the radius into the equation

( x - 2)^2 + ( y - 3)^2 = r^2

( x - 2)^2 + ( y - 3)^2 = 34

Therefore, the equation of the circle is

( x - 2)^2 + ( y - 3)^2 = 34

3 0

4 years ago