Here is an example I did of the problem hope it helps let me know if you need anything else~!
~<span>Cecildoesscience </span>
1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
9514 1404 393
Answer:
- northbound: 2.5 hours
- southbound: 1.5 hours
Step-by-step explanation:
When the second train leaves the station, the trains are already 63 miles apart. The rate of increase of their separation is (57 +63) = 120 miles per hour. The remaining 243-63 = 180 miles of separation will be achieved in ...
(180 mi)/(120 mi/h) = 1.5 h
The northbound train will have traveled 2.5 hours; the southbound train will have traveled 1.5 hours when the trains are 243 miles apart.
Answer:
49
Step-by-step explanation:
delta math said it
Answer:
y=a-4 divided 3-a and a cut so remember 4divided3 so, y= 1.33
Step-by-step explanation:
