Answer:
(- 5, 2 )
Step-by-step explanation:
Under a reflection in the line y = x
a point (x, y ) → (y, x ), thus
(2, - 5 ) → (- 5, 2 )
Will the answer to the expression is -4 but i don't see any arrows <span />
Answer:
4 + 2g
General Formulas and Concepts:
<u>Pre-Algebra</u>
Distributive Property
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
2(2 + g)
<u>Step 2: Expand</u>
- Distribute 2: 2(2) + 2(g)
- Multiply: 4 + 2g
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
B. (-2, 3).........................