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4 years ago

10

how much is 81% of 403? find the missing element in the following base-rate-percentage problem. round the answer to the nearest

hundredth.

1 answer:

mihalych1998 [28]4 years ago

5 0

4.03 x over 403 81 over 100 and cross multiply

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X/3=-19<br> What is the value of x

Molodets [167]

<h3>I'll teach you how solve X/3=-19</h3>

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X/3=-19

Multiply both sides by 3:

3x/3= 3(-19)

Simplify:

x= -57

Your Answer Is x= -57

plz mark me as brainliest :)

8 0

3 years ago

Read 2 more answers

If jobs arrive every 15 seconds on average, what is the probability of waiting more than 30 seconds?

Aleksandr [31]

Answer: 0.14

Step-by-step explanation:

Given: Mean : $\lambda=15\text{ per seconds}$

In minutes , Mean : $\lambda=4\text{ per minute}$

The exponential distribution function with parameter $\lambda$ is given by :-

$f(t)=\lambda e^{-\lambda t}, \text{ for }x\geq0$

The probability of waiting more than 30 seconds i.e. 0.5 minutes is given by the exponential function :-

$P(X\geq0.5)=1-P(X\leq0.5)\\\\=1-\int^{0.5}_{0}4e^{-4t}dt\\\\=1-[-e^{-4t}]^{0.5}_{0}\\\\=1-(1-e^{-2})=1-0.86=0.14$

Hence, the probability of waiting more than 30 seconds = 0.14

5 0

3 years ago

Mount Rogers rises 1/4 mile above sea level. Mount Taylor rises 6 times as high as Mount Rogers. Mount Sullivan rises 2 times as

galben [10]

1 mile is the difference between mount Taylor and mount Sullivan

6 0

2 years ago

In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study

DIA [1.3K]

Answer:

$z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055$

The p value can be calculated from the alternative hypothesis with this probability:

$p_v =2*P(Z>2.055)=0.0399$

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

$X_{1}=1642$ represent the number of smokers from the sample in 1995

$X_{2}=1415$ represent the number of smokers from the sample in 2010

$n_{1}=4276$ sample from 1995

$n_{2}=3908$ sample from 2010

$p_{1}=\frac{1642}{4276}=0.384$ represent the proportion of smokers from the sample in 1995

$p_{2}=\frac{1415}{3908}=0.362$ represent the proportion of smokers from the sample in 2010

$\hat p$ represent the pooled estimate of p

z would represent the statistic

$p_v$ represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

The statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374$

Replacing the info given we got:

$z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055$

The p value can be calculated from the alternative hypothesis with this probability:

$p_v =2*P(Z>2.055)=0.0399$

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0

3 years ago

Identify the action-reaction pair when a softball player hits a home run

Mariulka [41]

Answer:

Newton's third law of motion states that every action has an equal and opposite reaction. In softball when the catcher catches the ball the two forces present are the mitt on the ball and the ball on the mitt. The two are equal and in opposite directions.

4 0

3 years ago