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3 years ago

It took 20 minutes to print out 250-pages report. at this speed,how many pages could this printer produce in 30 minutes

1 answer:

4 0

My answer: 375 pages
Reasoning: Well if it took 20mins to print 250 pages then divide both in half. 10mins to print out 125 pages. Then multiply both by 3. 30mins to print out 375 pages

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List the elements in the set.<br> 1) {x 1 x is an integer between -7 and -3}

omeli [17]

Answer:

सामाजिक अध्ययन र जिवनोपयोगी शिक्षाको महत्व दसांउनुहोस

8 0

2 years ago

Joe's Ice Cream Shop has 7/8 of a gallon of vanilla ice cream left. They use 1/12 of a gallon of ice cream to make one milkshake

Vadim26 [7]

Answer:

Ten and a Half milkshakes can be prepared from the available amount of ice cream.

Step-by-step explanation:

The total vanilla ice cream = 7/8 gallons

Ice cream used for 1 milkshake = 1/12 gallon

Now, total number of milkshakes possible = $\frac{\textrm{Total availibility of ice cream}}{\textrm{Ice cream used for each milkshake}}$

= $\frac{\frac{7}{8} }{\frac{1}{12} } = \frac{7}{8} \times \frac{12}{1} = 10.5$

Hence ten and a half milkshakes can be prepared from the available amount of ice cream.

8 0

3 years ago

Read 2 more answers

Can someone please help me with this question??

suter [353]

｡☆✼★ ━━━━━━━━━━━━━━━ ☾

Use this equation:

(difference/original) x 100

Substitute in the values:

(150/450) x 100

Solve:

percentage = 33.333

Thus, the answer is option B

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

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8 0

3 years ago

Read 2 more answers

Molly works at an electronics store. Her last customer purchased a DVD player for $67.65 and five DVDs for $57.93, including tax

ra1l [238]

67.65 + 57.93 = 125.58

200.00 - 125.58 = $74.42 change back

3 0

3 years ago

Is sin theta=5/6, what are the values of cos theta and tan theta?

mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill$

$\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}$

5 0

3 years ago