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3 years ago

5

Jack picks 3 liters of berries in 8 minutes. Jill picks 4 liters of berries in 10 minutes. Working together, how many berries ca

n they pick in 1 minute?

1 answer:

____ [38]3 years ago

8 0

Answer:

they can pick 27 berry's

Step-by-step explanation:

I think-

You might be interested in

Solve the inequality:-3x-4/7 >5

Aliun [14]

x < - $\frac{13}{7}$

add $\frac{4}{7}$ to both sides

- 3x > $\frac{4}{7}$ + $\frac{35}{7}$

- 3x > $\frac{39}{7}$ ( divide both sides by - 3 )

note that when we divide/ multiply by a negative quantity we must reverse the inequality symbol

x < - $\frac{13}{7}$

6 0

3 years ago

the combination for a lock is a 3 didget number the didgets are the prime factors of 42 listing from least to greatest what is t

zhannawk [14.2K]

42 = 2 * 3 * 7

So, <span>the combination for the lock is 237</span>

3 0

3 years ago

A store has 7 red shirts, 15 black shirts, 13 white shirts, and 5 green shirts. Select the portion of the shirts that are black.

Svetach [21]

First you must add all of the shirts together, which gives you: 40

Since 15 of those are black, then you need to put those 15 over the total number of 40, making it 15/40.

Then you must simplify by the highest number that will go into both, and since that number is 5, it will then go into 15 three times and it will go into 40 eight times.

That leaves you with the answer of: 3/8

Hope I helped and good luck on your test! Please mark as brainliest if right? :)

4 0

3 years ago

Suppose that the population of the scores of all high school seniors who took the SAT Math (SAT-M) test this year follows a Norm

Vlad1618 [11]

Answer:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

$X \sim N(\mu, \sigma)$

The distribution for the sample mean is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar x =512$ represent the sample mean

$\sigma=100$ represent the population standard deviation

n= 100 sample size selected.

The confidence interval is given by this formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$ (1)

The marginof error for this case is given by Me=25.76. And we know that the formula for the margin of error is given by:

$Me=z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

$25.76=z_{\alpha/2} \frac{100}{\sqrt{100}}$

And we can find the critical value $z_{\alpha/2}$ like this:

$z_{\alpha/2}=\frac{25.76(\sqrt{100})}{100}=2.576$

And we know that on the right tail of the z score =2.576 we have $\alpha/2$ of the total area. We can find the area on the right of the z score using this excel code:

"=1-NORM.DIST(2.576,0,1,TRUE)" or using a table of the normal standard distribution, and we got 0.004998= $\alpha/2$ , so then $\alpha=0.00498*2=0.009995 \approx 0.01$ , and then we can find the confidence like this:

Confidence = $1-\alpha=1-0.01=0.99$

And then the confidence level would be given by 99%

8 0

3 years ago

A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If the silo is to have a volume of 505π ft3,

Romashka-Z-Leto [24]

Answer:

radius x = 3 ft

height h = 23,8 ft

Step-by-step explanation:

From problem statement

V(t) = V(cylinder) + V(hemisphere)

let x be radius of base of cylinder (at the same time radius of the hemisphere)

and h the height of the cylinder, then:

V(c) = π*x²*h area of cylinder = area of base + lateral area

A(c) = π*x² + 2*π*x*h

V(h) = (2/3)*π*x³ area of hemisphere A(h) = (2/3)*π*x²

A(t) = π*x² + 2*π*x*h + (2/3)*π*x²

Now A as fuction of x

total volume 505 = π*x²*h + (2/3)*π*x³

h = [505 - (2/3)* π*x³ ] /2* π*x

Now we have the expression for A as function of x

A(x) = 3π*x² + 2π*x*h A(x) = 3π*x² + 505 - (2/3)π*x³

Taking derivatives both sides

A´(x) = 6πx - 2πx² A´(x) = 0 6x - 2x² = 0

x₁ = 0 we dismiss

6 - 2x = 0

x = 3 and h = [505 - (2/3)* π*x³]/2* π*x

h = (505 - 18.84) / 6.28*3

h = 23,8 ft

7 0

3 years ago