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Bezzdna [24]
3 years ago
6

How are real numbers used to describe real world situations

Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0
Real number are used to explain real situations by allowing you to understand that they will always have an outcome that is disable by another real number
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Given that
Ganezh [65]

Answer:

x^{2} -9x

Step-by-step explanation:

I will upload a picture with my work.

4 0
3 years ago
it cost Andrea $50 per day to rent a moving truck and an additional $3 for every mile that she drove it. It Andrea spent a total
Xelga [282]
104=3m-50 is the equation that I would use, because 104 is the total, and it’s 3 dollars per mile, and $50 of the total is the initial fee. Sorry if the explanation isn’t the best, I’m kinda bad at them haha. Good luck!
3 0
3 years ago
6n+7n<br> whats the answer
sergeinik [125]
13n





ahaha , it’s that easy !!






have a good day <3
3 0
2 years ago
Read 2 more answers
Three numbers that multiply to get to 24
mojhsa [17]

Answer: 1 x 24, 2 x 12, 3 x 8, and 4 x 6.

Step-by-step explanation: The factor pairs of 24 are: 1 x 24, 2 x 12, 3 x 8, and 4 x 6.

                                     Hope This Helps

3 0
3 years ago
Read 2 more answers
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
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