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3 years ago

100 is 1/10 of what? Someone please help

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Answer:

1000. 100x10=1000 100+100+100+100+100+100+100+100+100+100=1000

100/1000=1/10

Step-by-step explanation:

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What is the result when −2/3 subtracted from −14/15?

disa [49]

Step-by-step explanation:

14/15 - 2/3 =

14/15 and 2/3 lcm is 15

so 14/15 becomes 14/15

- 2/3 become 10/15

15÷5=3 and 10÷5=2

so 14/15

-10/15=4/15

14-10 = 4

answer is 4/15 and since 15 can't be divided by 4 equally it is in simplest form at 4/15

7 0

3 years ago

[-1 + (-4)] + (6/7 + 1/7)

Radda [10]

Answer:-4

Step-by-step explanation:

-1 +-4 is -5 and 6/7 + 1/7 =1 so -5 +1=-4

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3 years ago

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vaieri [72.5K]

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3 years ago

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yan [13]

The answer is $1.50.

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3 years ago

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Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace

joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean $\mu$ and default $\sigma$ , then the mean take seriously given as the straight line with a z score given by the confidence interval

$\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\$

Using formula:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

$P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)$

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

$=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z$

the required probability: $P(z>0.8349)=1-P(z$

4 0

3 years ago