Answer:
3:1
Step-by-step explanation:
The correct answer for this would be 240 hope this helps!
We have a system of equations here:
Let 'a' = adult tickets and 'c' = children's tickets
5.80c + 9.00a = 1056.20
We also know that the total number of tickets (adults and children) was 149:
a + c = 149
We need only solve the system.
We are to find the probability that the weight of total luggage for a sample of 100 passengers is less than 2100.
The mean weight of the luggage of passengers will be 2100/100 = 21.
So we have to find the probability of the mean weight to be less than 21.
Average weight = u = 19.4
Standard deviation = 5.3
Since we are dealing with a sample of 100. We will use the standard error.
Standard error =

Now we have to convert the weight to z-score

From z table we can find the probability of z being less than 3.018 is 99.87%.
Therefore, the probability that for (a random sample of) 100 passengers, the total luggage weight is less than 2,100 lbs is 99.87%
Answer: 0.00462962962...
Step-by-step explanation: