Tonisha has a lemonade stand. She has $25 in expenses and wants to make at least $55 per day.

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

5 0

Hello!

Your answer is:

x-31 ≥ 66⇒x ≥ 97!

Hopefully this helps! Please correct me if im wrong! :C

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Y=5x-10 how do i graph this

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5 0

3 years ago

What is the value of x when -25(x - 4) = -55(x - 10) ?

Free_Kalibri [48]

Simplify both sides of the equation

-25(x-4)=-55(x-10)

(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)

Distribute

-25x+100=-55x+550

Add 55x to both sides

-25x+100+55x=-55x+550+55x

30x+100-100=550-100

subtract 100 from both sides

30x+100-100=550-100

30x=450

divide both sides by 30

30x/30=450/30

x= 15

The value of x is 15

I hope that's help you my friend !

5 0

3 years ago

Read 2 more answers

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$