All categories

3 years ago

Which equation can you use to solve for figure shown?

Mathematics

2 answers:

DIA [1.3K]3 years ago

4 0

Hey mate

Here is ur answer ...

I hope it'll help ....

Fofino [41]3 years ago

3 0

Answer:

Second Question: What is the approximate value of ∅ in degrees?

Answer: 55.2

Step-by-step explanation:

You might be interested in

Geometry, please answer question ASAP

vladimir1956 [14]

Answer:

i think 60 degree is the answer

7 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line with slope 4 and y-intercept -5.

ArbitrLikvidat [17]

Answer:

y = 4x -5

Step-by-step explanation:

y = mx+b

m = slope

b = y-intercept

so y= 4x -5

7 0

3 years ago

Rewrite the quadratic function in vertex form.<br> Y=5x^2-10x+2

Natalka [10]

Answer:

y = 5x2 + 10x - 15

We want this in format y = a(x-h)2 + k

where the vertex will be at (h,k)

y = 5(x2+2x) - 15

Complete the square on x2+2x

y = 5(x2+2x+1) - 15 - 5

We subtract 5 at the end because we are actually adding 5(1) = 5

so we need to remove it also to keep the total equal

y = 5(x+1)2 - 20

The vertex is at (-1,-20)

3 0

3 years ago

A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below:

sasho [114]

To find the volume of this storage bin, you will use the formula for volume of a cylinder and of a cone.

V = Bh (cylinder)
Pi x r^2 x h
Pi x 2^2 x 10

V = 1/3 x pi x r^2 x h
1/3 x pi x 2^2 x 3

All of these choices show correct answers!

4 0

3 years ago

Assuming the amount of money college students spend on text books each semester is symmetrical with a mean of 500 and a standard

TiliK225 [7]

16% percent of the students paid MORE than Jane.

The mean(μ) of money spent on textbooks is 500

The standard deviation(σ) of money spent on textbooks is 50

Money paid by Jane for her books is $550

We will use this formula,

Ζ=x-μ/σ

To find: the percentage of students paid MORE than Jane for the textbooks

$P(X > 550)$ =?

Solution:

$P(X > 550)=1-P(X$ ≤ $550)$

= $1-P($ Ζ≤ $\frac{550-500}{50} )$

=1-P(Ζ≤ 1)

=1-0.8413

=0.1587

≈16%

Therefore, 16% percent (approx) of the students paid MORE than Jane.

Learn more about mean and standard deviation here brainly.com/question/4388715

#SPJ4

3 0

2 years ago