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dolphi86 [110]
3 years ago
8

The quotient of two consecutive positive integers is 1.02. What is the sum of these two integers?

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
8 0

Answer:It is 101 Good luck!!!!!

Nastasia [14]3 years ago
5 0
Let these two integers be called x and y.

We are told:

x = y + 1 (consecutive integers) EQN (1)

and

\frac{x}{y} =1.02 EQN (2)

Solving this system of equations gives

\frac{y+1}{y}  = 1.02

Solving yields

y = 50 and x = 51

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Step-by-step explanation:

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Gennadij [26K]

Answer:

12

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3 years ago
4x^2+2xy-10y^2+9=0 what is the value of a,b,c and the discriminant?
zavuch27 [327]

basically you treat y like a number and not a variable

Answer:

a is 4

b is 2y

c is -10y²+9

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Step-by-step explanation:

4x²+2xy-10y²+9=0

rewrite in standard form of a quadratic equation like ax² + bx + c = 0

4x²+2yx-10y²+9=0

basically you treat y like a number and not a variable

a is the number with the x²

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b is the one with x so in this formula b is 2y

c is the number without the x which in this case is -10y²+9

discriminant is

b² - 4ac

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4y²-(16)(-10y²+9)

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