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3 years ago

Find the solutions of each equation on the interval [0, 2π).

Mathematics

1 answer:

inysia [295]3 years ago

7 0

Answer:

x = 0

Step-by-step explanation:

Given sin(3π/2+x) + sin(3π/2+x) = -2

2sin(3π/2+x) = -2

sin(3π/2+x) = -1

clearly x = 0 on satisfies the above equation

We know that sin(3π/2+x) = - cosx

-cosx = -1

cosx = 1 Has only one solution at x=0 in x∈ [0,2π)

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