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torisob [31]
4 years ago
13

Find the solutions of each equation on the interval [0, 2π).

Mathematics
1 answer:
inysia [295]4 years ago
7 0

Answer:

x = 0

Step-by-step explanation:

Given sin(3π/2+x) + sin(3π/2+x) = -2

2sin(3π/2+x) = -2

sin(3π/2+x) = -1

clearly x = 0 on satisfies the above equation

We know that sin(3π/2+x) = - cosx

-cosx = -1

cosx = 1 Has only one solution at x=0 in x∈ [0,2π)

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DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 cm and BD=12 cm.
jonny [76]
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.

Given that </span><span>DG = 5 cm and BD = 12 cm, then

BG= \sqrt{DG^2+BD^2}  \\  \\ = \sqrt{5^2+12^2} = \sqrt{25+144}  \\  \\ = \sqrt{169} =13

Since AG = BG = CG, therefore, CG = 13 cm.</span>
3 0
3 years ago
What is the measure of angle P?<br><br> Round only your final answer to the nearest hundredth.
Svetradugi [14.3K]

Answer:

i think its 130

Step-by-step explanation:

hope this helps? :|

5 0
3 years ago
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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kaheart [24]

Answer:i would help but the picture is tooooo blurry

Step-by-step explanation:

7 0
3 years ago
I NEED HELP ASAP!!!!! WILL MARK BRAINLIEST!!!!!!
alexgriva [62]

Answer: 16

Step-by-step explanation:

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3 years ago
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