Find the solutions of each equation on the interval [0, 2π).
1 answer:
Answer:
x = 0
Step-by-step explanation:
Given sin(3π/2+x) + sin(3π/2+x) = -2
2sin(3π/2+x) = -2
sin(3π/2+x) = -1
clearly x = 0 on satisfies the above equation
We know that sin(3π/2+x) = - cosx
-cosx = -1
cosx = 1 Has only one solution at x=0 in x∈ [0,2π)
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