<h2>
Answer with explanation:</h2>
Formula to find the confidence interval for population proportion (p) is given by :-
, where z* = Critical value.
= Sample proportion.
SE= Standard error.
Let p be the true population proportionof U.S. adults who live with one or more chronic conditions.
As per given , we have
SE=0.012
By z-table , the critical value for 95% confidence interval : z* = 1.96
Now , a 95% confidence interval for the proportion of U.S. adults who live with one or more chronic conditions.:
Hence, a 95% confidence interval for the proportion of U.S. adults who live with one or more chronic conditions.
Interpretation : Pew Research Foundation can be 95% confident that the true population proportion (p) of U.S. adults who live with one or more chronic conditions lies between 0.42648 and 0.47352 .
Answer:
-3
Step-by-step explanation:
Pick two points on the graph, lets go with (0, 4) and (1, 1)
y = mx + b
m is the slope and to figure it out use below formula
m = (y₂ - y₁) / (x₂ - x₁)
= (1 - 4) / (1 - 0)
= -3 / 1
= -3
Constant of proportionality is 4
equation: x/y = 4
explanation:
let's take 20 and 5 for example, if you divide 20 by 5, you will 4 of course. that's the proportionality for the first one. if you continue to divide x value by y value you will get 4. for the last two you would divide 28 by 4 and multiply 8 by 4.
<span>The number can be 102, 108, or 114. They can all be formed that way.
32 + 34 + 36 = 102
34 + 36 + 38 = 108
36 + 38 + 40 = 114
</span>The n<span>ext one is 120 . . . . . 38 + 40 + 42</span>
The perimeter is 48 units
