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Leviafan [203]
3 years ago
6

Please answer this quick! Factor the equation

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

2x²(a-b) + x(b-a) + 6(b-a) = 2x²(a-b) - x(a-b) - 6(a-b) = (a-b)(2x²- x - 6)=

=(a-b)(2x+3)(x-2)

6x²(a-b) + x(a-b) + 12(b-a) = 6x²(a-b) + x(a-b) - 12(a-b) =(a-b)(6x²+x - 12)=

=(a-b)(3x - 4)(2x + 3)

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How do I slove this eqaution, and whats the answer?<br> -3(n+6)+10=-9
Sauron [17]

Answer:

n = \frac{1}{3}

Step-by-step explanation:

  1. Apply the distributed property, so it now looks like this: -3n + -18 + 10 = -9
  2. Combine like terms: -3n + -8 = -9
  3. Simplify: -3n - 8 = -9
  4. Add 8 to each side, so it now looks like this: -3n = -1
  5. Divide each side by -3 to cancel out the -3 next to n. It should now look like this: n = 1/3

I hope this helps!

8 0
3 years ago
Solve for x 3x + 2 y;y=
Nataly [62]

Answer:

I beleive its 6

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Order the following from least to greatest 0.222, 1/5, 0.02
lorasvet [3.4K]
1. Put all values in decimals

0.222=0.222

1/5= 0.2

0.02= 0.02

2. Order the cakes from least to greatest

0.02, 0.2, 0.222


Hope this helps!
6 0
3 years ago
Read 2 more answers
Perform the following operations and write the answers in radical form. Part A:√7+√3+√98−√18 Part B:3√5−3√11+2√121−3√90
Sveta_85 [38]

Answer:

  1. \sqrt{7}+\sqrt{3}+4\sqrt{2}
  2. 3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

Step-by-step explanation:

Part A ;

\sqrt{7} +\sqrt{3} +\sqrt{98} -\sqrt{18} \\\\\sqrt{98}=7\sqrt{2}\\\sqrt{18}=3\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+7\sqrt{2}-3\sqrt{2}\\\\\mathrm{Add\:similar\:elements:}\:7\sqrt{2}-3\sqrt{2}=4\sqrt{2}\\\\=\sqrt{7}+\sqrt{3}+4\sqrt{2}

Part B ;

3\sqrt{5}  - 3\sqrt{11} + 2\sqrt{121} -3\sqrt{90} \\\\2\sqrt{121}=22\\3\sqrt{90}=9\sqrt{10}\\\\=3\sqrt{5}-3\sqrt{11}+22-9\sqrt{10}

8 0
4 years ago
What is (2x^2+2x-6) times (x-4)?
andreev551 [17]

Answer:

2x^3-6x^2-14x+24

Step-by-step explanation:

7 0
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