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3 years ago

Can someone help me with the second question? The answer is ( 2, -3 ) but I’m not sure how you get it...

Mathematics

1 answer:

JulijaS [17]3 years ago

6 0

Answer:

(2,-3)

Step-by-step explanation:

-2x +3y = -13

-2x -5y = 11

Multiply the second equation by -1

2x +5y = -11

Add this to the first equation

-2x +3y = -13

2x +5y = -11

--------------------

8y = -24

Divide each side by 8

8y/8 = -24/8

y = -3

Now find x

2x +5y =-11

2x +5(-3) =-11

2x-15 =-11

Add 15 to each side

2x-15+15 = -11+15

2x =4

Divide each side by 2

2x/2 = 4/2

x =2

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

A regular pentagon shares a common center with a regular hexagon. If `bar(LM)` || `bar(AB)`, across how many lines of reflection

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our lines of symmetry is made limited by the presence of the pentagon. If we slice the pentagon into two, the only line of symmetry we could create would be the line intersecting O and the median of LM. Other lines would not create a symmetrical half.

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(jacemorris04)

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3 years ago

The altitude of a triangle is 2 m longer than its base. What are the dimensions of the altitude and the base if thearea of the t

HACTEHA [7]

Step-by-step explanation:

Let base of triangle be x m.

Therefore, altitude =( x + 2)m

$area \: of \: \triangle = \frac{1}{2} \times base \times altitude \\ \\ 40 = \frac{1}{2} \times x \times (x + 2) \\ \\ 80 = {x }^{2} +2x \\ \\ {x}^{2} + 2x - 80 = 0 \\ {x}^{2} + 10x - 8x - 80 \\ x(x + 10) - 8(x + 10) = 0\\ (x + 10)(x - 8) = 0 \\ x + 10 = 0 \: \: or \: \: x - 8 = 0 \\ x = - 10 \: \: or \: \: x = 8 \\ base \: can \: not \: be \: - ve \\ x \neq - 10 \\ x = 8 \\ x + 2 = 8 + 2 = 10 \\$

Therefore

Altitude = 10 m

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4 years ago