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GalinKa [24]
4 years ago
13

Find the vertex of y=(x-3)^2

Mathematics
1 answer:
Elza [17]4 years ago
3 0

The vertex form of parabola is,

y=a(x-p)^2+q

Where (p,q) is vertex point.

In this case our parabola is given by,

y=1(x-3)^2+0

Hence the vertex is at (3,0).

Hope this helps.

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A metronome is a device that ticks at adjustable intervals to help keep time when playing music. the metronome on ryan’s piano h
Andru [333]

When the metronome was created out of a piece of solid wood, the minimum amount of solid wood that was used from the pyramid will be C. 540 centimeters cubed.

<h3>How to calculate the pyramid?</h3>

From the information given, the metronome ticks at adjustable intervals to help keep time when playing music.

In rhis case, when the metronome was created out of a piece of solid wood, the minimum amount of solid wood that was used from the pyramid will be:

= 20 × 9 × ✓9

= 20 × 9 × 3

= 540

Learn more about pyramid on:

brainly.com/question/218706

#SPJ4

6 0
2 years ago
Read 2 more answers
Please help me with this
MissTica
Well its pretty hard let me see its 8 by cm  and  27 by aera
8 0
3 years ago
Which expression has a value of 35 when p = 7?
makvit [3.9K]

Answer:

5p

Step-by-step explanation:

if p=7, 5p=35

6 0
3 years ago
Read 2 more answers
Please help me!! Fake answers will be reported
Fantom [35]

Answer: Now, I'm not so sure about the identify and inconsistent part, so I took a guess.  Sorry if I'm wrong!

a. x = -8 (identify)

b. x = 6 (identify)

c. x = <em>5 = -1</em>  (inconsistent)

d. x = 6 (identify)

d. (the second d;  it looks like there are 2 <em>d</em>'s) x = 5 (identify)

e. 1 = -1 (inconsistent)

f. x =  \frac{2}{3} (identify)

g. x = -3 (identify)

h. 5x+5 = 5x+5 (identify)

i. I don't know, sorry :/

Step-by-step explanation:

a. 7x +5 = 2x - 35

  -2x        -2x   (Subtract the smaller number with the x)

 5x +5 = -35

      -5      -5

      5x = -40

         x = -8    (Divide 5 with 5x and -40)

b. \frac{x}{3} - 7 = -5

   x - 21 = -15   (Multiply 3 with x/3, -7, and -5)

          x = 6

c. 4x +5 = 4x -1

   -4x       -4x

            5 = -1

d. \frac{5(x-3)}{2} -1 = 14

10(x-3) -2 = 28  (Multiply all numbers by 2)

10x -30 -2 = 28   (Combine -30 and -2)

    10x -32 = 28

          +32  +32

           10x = 60

               x = 6

d. 3 (x-1) +2 = x+9

    3x -3 +2 = x+9

           3x -1 = x+9  (Subtract x from both sides b/c x is basically 1x)

           -x        -x

          2x -1 = 9

               +1  +1

               2x = 10

                  x = 5  (Divide 2 from both sides)

e. 4x-(2x-1) = x+5+x-6

4x -2x +1 = x+5+x-6  (Mulitply the negative sign w/ 2x and -1. The negative sign is basically a -1.  So, a negative times a negative is a positive)

        2x+1 = 2x -1 (You can stop here or keep going)

        -2x     -2x

              1 = -1

f. 5(2x-6)+2=(4x+3)=8x-9

10x-30+8x+6 = 8x-9

18x - 24 = 8x - 9

      +24         +24

       18x = 8x + 15

      -8x      -8x

      10x = 15  (Divide 10 by both sides)

          x = \frac{2}{3}

g. \frac{2x+5}{6} = \frac{x}{18}

   6x = 18(2x+5)

    6x = 36x+90

    -6x   -6x

      0 = 30x + 90

    -90          -90

    -90 = 30x  (Divide 30 by both sides)

      -3 = x

h. \frac{10x-4}{2} +7 = 5(x+1)

\frac{2(5x-2)}{2} +7 = 5(x+1)  (The 2 cancels out)

 5x - 2 + 7 = 5(x+1)  (Combine like terms and do distributive property)

        5x+5 = 5x+5  (We can stop here because each side is the same)

i. I'm so sorry, I don't quite know :/

3 0
3 years ago
The equation of motion of a particle is s = t3 − 3t, where s is in meters and t is in seconds. (Assume t ≥ 0.) (a) Find the velo
Fynjy0 [20]

Answer:

a) v(t) = 3 \cdot t^{2} - 3\\a(t) = 6 \cdot t, b) a(3) = 18\,\frac{m}{s^{2}}, c) a(1) = 6\,\frac{m}{s^{2}}

Step-by-step explanation:

a) The velocity and acceleration function are obtained by deriving the displacement function once and twice, respectively:

v(t) = 3 \cdot t^{2} - 3\\a(t) = 6 \cdot t

b) The acceleration of the particle at such instant is:

a(3) = 18\,\frac{m}{s^{2}}

c) The time when velocity is zero is:

3\cdot t^{2} - 3 = 0\\t^{2}-1 = 0\\t^{2}=1\\t = 1

The acceleration is:

a(1) = 6\,\frac{m}{s^{2}}

6 0
3 years ago
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