Answer:
18
hope this helps
have a good day :)
Step-by-step explanation:
Let
x----> the length side of the hypotenuse
y----> the length side of the <span>unknown leg
we know that
x=2*y----> equation 1
applying the Pythagoras Theorem
x</span>²=y²+3²-----> equation 2
substitute equation 1 in equation 2
[2*y]²=y²+3²----> 4*y²-y²=9-----> 3*y²=9----> y²=3
y=√3 ft
x=2*y----> x=2*√3 ft
the answer is
<span>the lengths of the three sides are
</span>hypotenuse=2√3 ft
one leg=√3 ft
other leg=3 ft
Answer:
The fractions you make from the coordinates on the graph is equal. If it is then the graph is proportional
Hope this helped
Answer:
432 in^2
Step-by-step explanation:
in similar quadrilaterals, the first point of one quad. corresponds to the first point of the other quad, so in this case UA corresponds with CH.
since CH is 3/4 the length of UA, we can also assume that the other sides in ZUCH are 3/4 the length of their corresponding sides in SQUA.
even though we don't know what quadrilateral SQUA and ZUCH are, we know the area of SQUA is 9/16 times less than ZUCH.
want some proof?
lets say SQUA and ZUCH are rectangle/square
ZUCH: 4X4 = 16
SQUA: 3X3 = 9
now lets say they are trapezoids. We will set ZUCH 2nd base to 8 and height to 16, therefore SQUA bases will be 3 and 6, and the height will be 12 (multiply ZUCH lengths by 3/4)
ZUCH = (b1+b2)(h)/2 = (4+8)(16)/2 = 96
SQUA = (b1+b2)(h)/2 = (3+6)(12)/2 = 54
simplify 96/54 = 16/9
now we can multiply 243 by our factor 16/9 to find the area of SQUA.
243 * 16/9 = 432 in^2
