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julia-pushkina [17]
3 years ago
15

Casey has n nick;es. megan has 4 times as many nickels as casey. write an expression fir the total number of nickels casey and m

egan have. then simplify the expression
Mathematics
2 answers:
shepuryov [24]3 years ago
8 0
Say that n=4. Casey has 4 nickles, and Megan has 4x4, or 16 nickles. Combined, they have 20 nickles, or (5x4) nickles. Answer is 5n.
vladimir2022 [97]3 years ago
4 0
The anwser is 5n.....
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I'd love some help on this question. I do not understand how you would go about working this out, so please explain the working
zhannawk [14.2K]
Area = length x width and volume = length x width x height soo you would have to multiple 4 and 25 and that’s 100
7 0
3 years ago
I can’t figure this out!! please helppp
krok68 [10]

Answer:

The third answer

Step-by-step explanation:

(side note: You probably need to use a calculator that can calculate pi)

The formula to find the area of a circle is pi r squared.

In this case, pi times r squared is 19.63495....... continued

This is probably going to be rounded

so... 19.63

For all of the circles, this is multiplied by 4.

This is 78.52

The area of the square is 100 cm since 10 times 10 is 100

You take 100 cm and then subtract it by 78.54

Voila! now you have 21.46

3 0
3 years ago
Read 2 more answers
What’s the product of 0.54(8)
maw [93]

The answer to your problem is 4.32.

6 0
3 years ago
One circular table has a diameter of 9 ft, and another circular table has a diameter of 20 ft. How much greater is the area of t
morpeh [17]
Smaller circle:
diameter = 9 ft
radius = diameter/2 = (9 ft)/2 = 4.5 ft
A = pi(r^2) = 3.14159 * (4.5 ft)^2 = 63.62 ft^2

Larger circle:
diameter = 20 ft
radius = diameter/2 = (20 ft)/2 = 10 ft
A = pi(r^2) = 3.14159 * (10 ft)^2 = 314.159 ft^2

Difference = larger are - smaller area

Difference = 314.16 ft^2 - 63.62 ft^2 = 250.54 ft^2

Answer: About 251 ft^2
5 0
3 years ago
1)cot a/2 -tan a/2 = 2 cot a<br>2) cot b/2 + tan b/2= 2 cosec b<br> prove​
VladimirAG [237]
1)

LHS = cot(a/2) - tan(a/2)

= (1 - tan^2(a/2))/tan(a/2)

= (2-sec^2(a/2))/tan(a/2)

= 2cot(a/2) - cosec(a/2)sec(a/2)

= 2(1+cos(a))/sin(a) - 1/(cos(a/2)sin(a/2))

= 2 (1+cos(a))/sin(a) - 2/sin(a)) (product to sums)

= 2[(1+cos(a) -1)/sin(a)]

=2cot a

= RHS

2.

LHS = cot(b/2) + tan(b/2)

= [1 + tan^2(b/2)]/tan(b/2)

= sec^2(b/2)/tan(b/2)

= 1/sin(b/2)cos(b/2)

using product to sums

= 2/sin(b)

= 2cosec(b)

= RHS
8 0
3 years ago
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