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shutvik [7]
3 years ago
15

What is the slope and y-intercept of the graph?

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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How many terms are there in a geometric series if the first terms is 2, the common ratio is 4, and the sum of the series is 2,73
arsen [322]
The sum of n terms of a geometric series is given by
S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}

Substituting the given numbers, you have
2730=2\dfrac{4^{n}-1}{4-1}\\\\2730\dfrac{3}{2}=4^{n}-1\\\\4096=4^{n}\\\\\dfrac{\log(4096)}{\log(4)}=n=6

There are 6 terms in the series.
4 0
3 years ago
A basketball player scored 26 points in one game. In basketball, some baskets are worth 3 points, some are worth 2 points, and f
Vsevolod [243]

Answer:

3 points = 2

2 points = 6

1 point = 8

Step-by-step explanation:

Given that:

Total point scored = 26

Let number of 3 point basket = x

Number of 2 point basket = x + 4

Number of free throws = x + x + 4 = 2x + 4

Hence,

Total 3 points = 3x

Total 2 points 2(x + 4)

Total free throw points = 2x + 4

3x + 2(x + 4) + 2x + 4 = 26

3x + 2x + 8 + 2x + 4 = 26

7x + 12 = 26

7x = 26 - 12

7x = 14

x = 2

Number of 3 points = x = 2

2 points = (x+4) = 2+4 = 6

1 point = (2x+ 4) = 2(2) + 4 = 8

5 0
3 years ago
Read 2 more answers
Add: 3x(x-y+z) and 2y (x+y-z)​
hodyreva [135]

Answer:

3x^2 + 3xz + 2y^2 - 2yz - xy

Step-by-step explanation:

(1) multiply it to get

3x^2 - 3xy + 3xz and 2yx + 2y^2 - 2yz

add similar variables (-3xy + 2yx)

( the order of the variables doesn't matter xy or yx is the same)

we get -xy

and then after that simplifying we get 3x^2 + 3xz + 2y^2 - 2yz - xy

3 0
3 years ago
Read 2 more answers
Please Help!!! 30 Points!!!<br><br> Find X.<br><br> Please explain how you got your answer.
lidiya [134]
X= 38.12325882663022

First take SOHCAHTOA
We’ll use SOH.
SOH means sine(angle)=opposite/hypotenuse.

So sine(43 degrees)=26/X
Which means 26/(sine(43 degrees))=X
Which means 26/0.681998360062499=X
7 0
3 years ago
find continued product of (x+y) (x-y) (<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}"
leonid [27]

Answer:

\large\boxed{(x+y)(x-y)(x^2+y^2)(x^4+y^4)=x^8-y^8}

Step-by-step explanation:

(x+y)(x-y)(x^2+y^2)(x^4+y^4)\\\\\text{use}\ (a-b)(a+b)=a^2-b^2\qquad(*)\\\\=\underbrace{(x+y)(x-y)}_{(*)}(x^2+y^2)(x^4+y^4)\\\\=\underbrace{(x^2-y^2)(x^2+y^2)}_{(*)}(x^4+y^4)\\\\=\left((x^2)^2-(y^2)^2\right)(x^4+y^4)\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\underbrace{(x^4-y^4)(x^4+y^4)}_{(*)}\\\\=\left(x^4\right)^2-\left(y^4\right)^2=x^8-y^8

7 0
3 years ago
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