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4 years ago

11

Jackson weighed 6 pounds 3 ounces when he was born. When he was 4 weeks old, he weighed 128 ounces. How much weight did jacskon

gain in those 4 weeks?

1 answer:

riadik2000 [5.3K]4 years ago

6 0

He gained 8 lbs (pounds ) and lb is like 16 and there is 16 oz (ounces ) in a pound so 128 divided by 16 = 8

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1. 72% of the students in Math 6 at AZVA are currently passing mastering their lessons. If 324 students are currently mastering

Alexeev081 [22]

Answer:

<u>1. a. 72/100 = 324/x</u>

<u>72x = 32,400</u>

<u>b. 450 students are in Math 6</u>

<u>2. a. o = 3b</u>

<u>b. o = 3 pounds</u>

<u>3. a. Most popular animals:</u>

<u>A. Dogs - 67%</u>

<u>B. Cats - 20%</u>

<u>C. Other - 8%</u>

<u>D. None - 4%</u>

<u>E. Horses - 1%</u>

<u>b. 20 students</u>

<u>c. If 75 students have cats, the estimate of 250 students isn't correct.</u>

<u>The actual number of students interviewed is 375.</u>

Step-by-step explanation:

1. a. Let's use the following equation to solve the question:

x = Students that are in Math 6

72/100 = 324/x

72 * x = 324 * 100

72x = 32,400

b. Let's solve the equation, as follows:

x = 32,400/72

x = 450

<u>450 students are in Math 6</u>

2. a. The equation is:

o = 0.15 *20b

<u>o = 3b</u>

where, o = weight of oats in pounds and b = number of dog food bags

b. Let's find out the weight of the oats in one dog food bag, using our equation:

o = 0.15 *20b

o = 0.15 *20 * 1

<u>o = 3 pounds</u>

3. a. Most popular animals:

A. Dogs - 67%

B. Cats - 20%

C. Other - 8%

D. None - 4%

E. Horses - 1%

b. If 250 students were interviewed, the 8% who answered "other" are:

8% of 250 = 0.08 * 250 = <u>20 students</u>

c. If 75 students have cats, the estimate of 250 students isn't correct.

The 20% of 250 is 50, not 75.

0.2 * 250 = 50

The actual number of students interviewed is:

x = Actual number of students interviewed

75/x = 20/100

20x = 7,500

x = 7,500/20

x = 375

<u>The actual number of students interviewed is 375.</u>

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3 years ago

2. To build a Histogram from a frequency table, first we need to s____<br> __the data.

Butoxors [25]

Answer:

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Step-by-step explanation:

Here is the link that i used to research the answer

https://www.sparknotes.com/math/algebra1/graphingdata/section2/

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3 years ago

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What is the surface area of the solid figure represented by the net?

Ivenika [448]

Answer:

Option B. 373.80 square centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The surface area of the figure is equal to the area of its 5 faces (3 rectangular faces plus 2 triangular faces)

step 1

Find the area of its 3 rectangular faces

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$A_2=(12.7)(9.4)=119.38\ cm^2$

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step 2

Find the area of its 2 triangular faces

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$A_5=\frac{1}{2}(12.7)(5.6)=35.56\ cm^2$

step 3

Find out the surface area

$SA=A_1+A_2+A_3+A_4+A_5$

substitute the values

$SA=52.64+119.38+130.66+35.56+35.56$

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3 years ago

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Find the gradient of the line segment between the points (-5,2) and (4,3) give your answer in the simplest form

Leokris [45]

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Step-by-step explanation:

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Given points of the line segment: (-5,2) and (4,3)

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$\text{Gradient} =\dfrac{1}{4+5)}$

$\text{Gradient} =\dfrac{1}{9}$

Therefore , the gradient of the line segment between the points (-5,2) and (4,3) is $\dfrac{1}{9}$ .

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3 years ago

(3x-7)+(4x-8) what is the sum of this question pls

Papessa [141]

Answer:

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3 years ago

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