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statuscvo [17]
3 years ago
7

Please help me solve question 23

Mathematics
2 answers:
const2013 [10]3 years ago
8 0
I.\\a=\dfrac{(bc^3)^2}{14}\ \ \ \ |multiply\ both\ sides\ by\ 14\\\\14a=(bc^3)^2\\\\14a=b^2c^{3\cdot2}\\\\14a=b^2c^6-\fbox{:)}\\\\II.\\14a=(bc^4)^2\\\\14a=b^2c^{4\cdot2}\\\\14a=b^2c^8-\fbox{:(}\\\\III.\\ab^{-2}=\dfrac{c^6}{14}\ \ \ \ |multiply\ both\ sides\ by\ 14\\\\14ab^{-2}=c^6\ \ \ \ |multiply\ both\ sides\ by\ b^2\\\\14ab^{-2+2}=b^2c^6\\\\14a=b^2c^6-\fbox{:)}\\\\Answer:\boxed{(E)\ I\ and\ III\ only}
Fiesta28 [93]3 years ago
6 0
Expression I and expression III are both equivalent to it.
Expression II isn't.
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