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ELEN [110]
3 years ago
5

Use the expression 5(6 + 4x) to answer the following:

Mathematics
1 answer:
Ronch [10]3 years ago
7 0
Part A: 6 and 4x are the two factors because the initial equation was 30+20x but they factored out a 5 from both 30 and 20 to make the new equation
Part B:there are 3 terms in this expression
Part C:The coefficient of the variable X is 4
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Express ln 32 - ln 8 as a single natural logarithm
ivanzaharov [21]
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ln(32)-ln(8)\implies ln\left( \frac{32}{8} \right)\implies ln(4)
8 0
3 years ago
Read 2 more answers
If f(x)=x+7 and g(x)= 1 divided by x-13, what is the domain of (f•g)(x)?
andrew11 [14]
<h2>Hello!</h2>

The answer is:

The domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

<h2>Why?</h2>

This is a composite function problem. To solve it, we need to remember how to composite a function. Composing a function consists of evaluating a function into another function.

Composite function is equal to:

f(g(x))=(f\circ} g)(x)

So, the given functions are:

f(x)=x+7\\\\g(x)=\frac{1}{x-13}

Then, composing the functions, we have:

f(g(x))=\frac{1}{x-13}+7\\

Therefore, we must remember that the domain are all those possible inputs where the function can exists, most of the functions can exists along the real numbers with no rectrictions, however, for this case, there is a restriction that must be applied to the resultant composite function.

If we evaluate "x" equal to 13, the denominator will tend to 0, and create an indetermination since there is no result in the real numbers for a real number divided by 0.

So, the domain of the function is all the real numbers except the number 13:

Domain: (-∞,13)∪(13,∞)

Have a nice day!

5 0
3 years ago
After eating 25 percent of the pretzels, Sonya had 42 left how many pretzels did Sonya have originally??? How do I get the Answe
madreJ [45]
42 + 25% = 52 ( 25% is 1/4)
7 0
3 years ago
Can anyone help me with this
Wittaler [7]

I believe the right anwser is c

4 0
3 years ago
A student has passed 60 percent of the 20 quizzes he has written so far successfully. If the student writes 50 quizzes during th
NikAS [45]

60% of 20 quizzes = 60/100*20 quizzes = 12 quizzes

Amount of quizzes remaining = 50 quizzes - 20 quizzes = 30 quizzes

He passes 80% of those 30 quizzes, so

80/100 * 30 quizzes = 24 quizzes

So, he passed 12 quizzes from the initial bunch and 24 quizzes from the rest, which totals to 12 quizzes + 24 quizzes = 36 quizzes.

Then, you see that he passed 36 quizzes, out of the total 50 quizzes, so the ratio is 36 quizzes / 50 quizzes = 36/50, which when converted as a percentage is 36/50 * 100% = 72%.

Therefore, he passed 72% of the quizzes for the entire year.

4 0
3 years ago
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