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Aloiza [94]
3 years ago
10

4x-(5-x)=8[4-(8+2x-1)]

Mathematics
1 answer:
Alex Ar [27]3 years ago
8 0
4x-(5-x)=8[4-(8+2x-1)]
answer: x= -19/21
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Abe spent $144.00 for four bags of grass seed. How much did he spend on each bag
EastWind [94]

Answer:

Abe spent 36 dollars on each bag

Step-by-step explanation:

divide 144 by 4 (because there are 4 bags in total, and he spent 144 dollars)

the answer will be 36

3 0
3 years ago
Read 2 more answers
What is the dilation for the transformation below?​
lys-0071 [83]

Answer:

The dialation is of 2

Step-by-step explanation:

QR = 3 units

QS = 2 units

RS = 2 units

Q'R' = 6 units

Q'S' = 4 units

R'S' = 4 units

So as you can see, this triangle has doubled it's size, since it has been multiplied by 2.

Hope this helped!

Have a supercalifragilisticexpialidocious day!

4 0
3 years ago
Solve for x<br> x + y = 1<br> x + 7y = -4<br> 2x - 6y = 4<br> 5x + 15y = -10<br> 2x + 6y = 10
Arada [10]
X + y = 1
add - y both sides
x + y +  - y = 1 +  - y
x =  - y + 1
Answer: x =  - y + 1
Graph: y =  - x + 1


x + 7y =  - 4
add - 7 both sides
x + 7y +   - 7y = - 4 +  -7y
x =  - 7y  - 4
Answer: x = - 7y   - 4
Graph: y = 0.142857x  -  0.571429


2x  - 6y = 4
add 6y to both sides
2x  - 6y + 6y = 4 + 6y
2x = 6y + 4
divide both sides by 2
2x/2 = 6y + 4/2
x = 3y + 2
Answer: x = 3y + 2
Graph: y = 0.333333x  -  0.666667



5x + 15y = - 10
add - 15 to both sides
5x + 15y +   - 15y = - 10 +  - 15y
5x = - 15y  - 10
divide both sides by 5
5x/5 =  - 15y - 10/5
x = - 3y  - 2
Answer: x = - 3y - 2
Graph: y =  - 0.333333x  -  0.666667



2x + 6y = 10
add - 6y to both sides
2x + 6y +  - 6y = 10 +  - 6y
2x =  - 6y + 10
divide both sides by 2
2x/2 = - 6y + 10/2
x =  - 3y + 5
Answer: x =  -3y + 5
Graph: y =  - 0.333333x  +  1.666667





Hope that helps!!!
8 0
3 years ago
2.1 x 10^10 OVER 7 x 10^17
vlabodo [156]
2.1 x 10^10/ 7 x 10^17 
= 3 x 10^-8

hope this helps and have a great day :)


4 0
3 years ago
Read 2 more answers
Construct a truth table for the statement ~( p v ~q) <br> pq Truth Table
Likurg_2 [28]

Hello

T for True

F for False

\left|\begin{array}{c|c|c|c|c}p&q&\~q&pv\~q&\~(pv\~q)\\---&---&---&---&---\\T&T&F&T&F\\T&F&T&T&F\\F&T&F&F&T\\F&F&T&T&F\\\end{array}\right|

thanks

4 0
3 years ago
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